The minimum voltage required to electrolyse of ${\mathrm{Al}}_2{\mathrm{O}}_3$ in the Hall-Heroult process is:

Given : $\mathrm{\Delta G}{°}_{\mathrm{f}}\left({\mathrm{Al}}_2{\mathrm{O}}_3\right)=-1520 \mathrm{kJ} {\mathrm{mol}}^{-1}$  ;   $\mathrm{\Delta G}{°}_{\mathrm{f}}\left({\mathrm{CO}}_2\right)=-394 \mathrm{kJ} {\mathrm{mol}}^{-1}$

If the net reaction in the Hall-Heroult process is : $3\mathrm{C}+2{\mathrm{Al}}_2{\mathrm{O}}_3\to 4\mathrm{Al}+3{\mathrm{CO}}_2$

(Report your answer as voltage $10$)