The molar specific heat of the process $V\propto T^4$, for $C{H}_4$ gas, at room temperature, is

The first law of thermodynamics is a special case of,

A given quantity of gas is taken from the state $\mathrm{A}$ to the state $\mathrm{C}$ reversibly by two paths, $\mathrm{A}\to \mathrm{C}$ directly and $\mathrm{A} \to \mathrm{B}\to \mathrm{C}$ as shown in the figure below:

During the process $\mathrm{A}\to \mathrm{C}$, work done by the gas is $100 \mathrm{J}$ and heat absorbed is $120 \mathrm{J}$. If during the process $\mathrm{A}\to \mathrm{B}\to \mathrm{C}$, the work done by the gas is $80 \mathrm{J}$, the heat absorbed is