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The moment of inertia of a disc of radius 0.5 m about its geometric axis is 2 kg m2. If a string is tied to its circumference and a force of 10 N is applied, the value of torque with respect to this axis will be:

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Important Questions on Rotational Mechanics

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The moment of inertia of a disc of radius 0.5 m about its geometric axis is 2 kg m2. If a string is tied to its circumference and a force of 10 N is applied, if the disc executes rotatory motion, its angular acceleration will be:-
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The moment of inertia of a disc of radius 0.5 m about its geometric axis is 2kg-m2. If a string is tied to its circumference and a force of 10 Newton is applied, if the disc executes rotatory motion, the value of its angular velocity after 2 seconds will be :-
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The moment of inertia of a disc of radius 0.5 m about its geometric axis is 2 kg m2. If a string is tied to its circumference and a force of 10 N is applied, if the disc executes rotatory motion, the change in angular momentum of the disc in the first 2 seconds (in N m second) will be-
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The moment of inertia of a disc of radius 0.5 m about its geometric axis is 2 kg m2. If a string is tied to its circumference and a force of10 N is applied, the angular displacement of the disc, in the first two seconds will be (in radian):
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A particle of mass M and radius of gyration K is rotating with angular acceleration α. The torque acting on the particle is,
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The grinding stone of a flour mill is rotating at 600 rad s-1. For this, power of 1.2 kW is used. The effective torque on stone (in N m) will be
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A rigid body is rotating about an axis. To stop the rotation, we have to apply
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A wheel has a moment of inertia 5×10-3 kg m2 and is making 20 rev sec-1. The torque needed to stop it in 10 sec is...×10-2 N m: