Alpha Question Bank for Engineering: Chemistry>Chapter 27 - Aldehydes, Ketones and Carboxylic Acids>Exercise-4>Q 56

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The most unstable compound is

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Important Questions on Aldehydes, Ketones and Carboxylic Acids

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Alpha Question Bank for Engineering: Chemistry>Chapter 27 - Aldehydes, Ketones and Carboxylic Acids>Exercise-4>Q 57

The product obtained when propanamide is distilled with phosphorus pentoxide is

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Alpha Question Bank for Engineering: Chemistry>Chapter 27 - Aldehydes, Ketones and Carboxylic Acids>Exercise-4>Q 58

What is the major product obtained from the following reaction?

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Alpha Question Bank for Engineering: Chemistry>Chapter 27 - Aldehydes, Ketones and Carboxylic Acids>Exercise-4>Q 59

What is the major product obtained from the following reaction? ?

${CH}_{3} {COCH}_{2} COOH \overset{heat}{\to}$ Product

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Alpha Question Bank for Engineering: Chemistry>Chapter 27 - Aldehydes, Ketones and Carboxylic Acids>Exercise-4>Q 60

{CH}_{3} {CH}_{2} CH (OH) CH {({CH}_{3})}_{2} + {CH}_{3} COCl \overset{base}{\to} {CH}_{3} {CH}_{2} CH ({OCOCH}_{3}) CH {({CH}_{3})}_{2} + HCl

In the above reaction, if the reactant alcohol is pure

R

-isomers, the product would.

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Alpha Question Bank for Engineering: Chemistry>Chapter 27 - Aldehydes, Ketones and Carboxylic Acids>Exercise-4>Q 61

The major product $(Y)$ of the following reaction is -

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Alpha Question Bank for Engineering: Chemistry>Chapter 27 - Aldehydes, Ketones and Carboxylic Acids>Exercise-4>Q 62

4

-amino-

3

-methylbutanoic acid is treated with thionyl chloride followed by ammonia to obtain compound "

X

". "

X

" on reaction with bromine in an alkaline medium gave the compound "

Y

". For estimation "

Y

", was titrated with perchloric acid. The volume of

0.1 M

perchloric acid needed to react with

0.22 g

of "

Y

" is

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Alpha Question Bank for Engineering: Chemistry>Chapter 27 - Aldehydes, Ketones and Carboxylic Acids>Exercise-4>Q 63

When semicarbazide reacts with a ketone (or aldehyde) to form semicarbazone. Only one nitrogen atom of semicarbazide acts as a nucleophile and attacks the carbonyl carbon of the ketone. The product of the reaction, consequently, is

R_{2} C = N - NH - {CONH}_{2}

rather than

R_{2} C = NCONH - {NH}_{2}

. What factor account for the fact that two nitrogen atoms of semicarbazide are relatively non-nucleophilic?

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Alpha Question Bank for Engineering: Chemistry>Chapter 27 - Aldehydes, Ketones and Carboxylic Acids>Exercise-4>Q 64

Arrange the following compounds in decreasing orders of $K_{eq}$ for hydrate formation.

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