The negation of the Boolean expression $\left(\left(~q\right)\wedge p\right)\Rightarrow \left(\left(~p\right)\vee q\right)$ is logically equivalent to

Let $p,q,r$ be three logical statements. Consider the compound statements
$S_1:\left(\left(~p\right)\vee q\right)\vee \left(\left(~p\right)\vee r\right)$ and $S_2:p\to \left(q\vee r\right)$
Then, which of the following is NOT true?