A parallel-plate capacitor consists of 26 metal strips, each of 3 cm × 4 cm , separated by mica sheets of dielectric constant 6 and uniform thickness 0 . 2 mm . Find the capacitance.

Given that, Number of metal strip n = 26 Each of cross- sectional area, A = 3 cm × 4 cm Dielectric constant of the paper, k = 6 Thickness of each parallel plate capacitor, d = 0 .2 mm = 0 . 2 × 10 - 3 m Arrangement of n metal plates separated by dielectric acts as a parallel combination of n - 1 capacitors. Capacitance of n - 1 capacitors is ∴ C = n - 1 k ε 0 A d = 25 × 6 × 8 .85 × 10 - 12 × 3 × 4 × 10 - 4 0 .2 × 10 - 3 = 7 .97 × 10 - 9 F

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The net capacitance of three identical capacitors in of series is $1 μ F$ . What will be their net capacitance if connected in parallel?

Important Questions on Electrostatic Potential and Capacitance

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New Simplified Physics (Vol 1) For Class 12>Chapter 2 - Electrostatic Potential and Capacitance>Problems For Practice>Q 8

Figure shows a network of five capacitors connected to a $100 V$ supply. Calculate the total charge and energy stored in the network.

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New Simplified Physics (Vol 1) For Class 12>Chapter 2 - Electrostatic Potential and Capacitance>Problems For Practice>Q 9

Two capacitors are in parallel and the energy stored is $45 J$ , when the combination is raised to the potential of $3000 V$ . With the same two capacitors in series, the energy stored is $4.05 J$ for the same potential. What are their individual capacitances?

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New Simplified Physics (Vol 1) For Class 12>Chapter 2 - Electrostatic Potential and Capacitance>Problems For Practice>Q 10

Find the ratio of the potential differences that must be applied across the parallel and the series combination of two capacitors

C_{1}

and

C_{2}

with their capacitances in the ratio $1 : 2$ so that the energy stored in the two cases, becomes the same.

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12th CBSE

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New Simplified Physics (Vol 1) For Class 12>Chapter 2 - Electrostatic Potential and Capacitance>Problems For Practice>Q 1

A parallel-plate capacitor having plate area

100 {cm}^{2}

and separation

1.0 mm

holds a charge of

0.12 μ C

μC when connected to a

120 V

battery. Find the dielectric constant of the material filling the gap.

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New Simplified Physics (Vol 1) For Class 12>Chapter 2 - Electrostatic Potential and Capacitance>Problems For Practice>Q 2

Find the length of the paper used in a capacitor of capacitance

2 μ F

, if the dielectric constant of the paper is

2.5

and its width and thickness are

50 mm

and

0.05 mm

, respectively.

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12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 2 - Electrostatic Potential and Capacitance>Problems For Practice>Q 3

A parallel-plate capacitor consists of

26

metal strips, each of

3 cm \times 4 cm

, separated by mica sheets of dielectric constant 6 and uniform thickness

0.2 mm

. Find the capacitance.

EASY

12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 2 - Electrostatic Potential and Capacitance>Problems For Practice>Q 4

A parallel-plate capacitor of capacity

0.5 μ F

is to be constructed using paper sheets of thickness

0.04 mm

as dielectric. Find how many circular metal foils of diameter

0.1 m

will have to be used. Take the dielectric constant of paper used as

4

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12th CBSE

IMPORTANT

New Simplified Physics (Vol 1) For Class 12>Chapter 2 - Electrostatic Potential and Capacitance>Problems For Practice>Q 5

When a slab of insulating material

4 mm

thick is introduced between the plates of a parallel plate capacitor, it is found that the distance between the plates has to be increased by

3.2 mm

to restore the capacitance to the original value. Calculate the dielectric constant of the material.

The net capacitance of three identical capacitors in of series is 1 μF. What will be their net capacitance if connected in parallel?

Important Questions on Electrostatic Potential and Capacitance

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The net capacitance of three identical capacitors in of series is $1 μ F$ . What will be their net capacitance if connected in parallel?