EASY
Earn 100

The number of accidents on a certain road has a Poisson distribution with mean 3.1 per 12-week peroid 

Given that the mean number of accidents per week is now 0.1, find the probability of a Type II error.

Important Questions on Linear Combinations of Random Variables

MEDIUM
An unbiased coin is tossed 5 times. Suppose that a variable X is assigned the value k when k consecutive heads are obtained for k=3,4,5, otherwise X takes the value -1. Then the expected value of X, is
HARD
In a game, a man wins Rs. 100 if he gets 5 or 6 on a throw of a fair die and loses Rs. 50 for getting any other number on the die. If he decides to throw the die either till he gets a five or a six or to a maximum of three throws, then his expected gain/loss (in rupees) is :
MEDIUM
A boy tosses fair coin 3 times. If he gets ₹ 2x for x heads then his expected gain equals to ₹........
HARD
If 'X' has a binomial distribution with parameters n=6, p and P(X=2)=12, P(X=3)=5, then p=
HARD
The mean of 5 observations is 5 and their variance is 12.4. If three of the observations are 1,2 & 6; then the value of the remaining two is :
MEDIUM

A random variable X has the following probability distribution

X 1 2 3 4 5 6 7
P(X) K-1 3K K 3K 3K2 K2 K2+K
MEDIUM
A box contains 6 pens, 2 of which are defective. Two pens are taken randomly from the box. If random variable x: Number of defective pens obtained, then standard deviation of x=
HARD
If the function f defined by fx=Kx-x2;   if 0<x<10;    otherwise is the probability density function of a random variable X, then the value of PX<12 is
MEDIUM
The mean and variance for seven observations are 8 and 16 respectively. If 5 of the observations are 2,4,10,12,14, then the product of the remaining two observations is
MEDIUM
The mean and variance of 8 observations are 10 and 13.5, respectively. If 6 of these observations are 5,7,10,12,14,15, then the absolute difference of the remaining two observations is :
MEDIUM
Let xi1i10 be ten observation of a random variable X. If i=110xi-p=3 and i=110xi-p2=9 where 0pR, then the standard deviation of these observations is:
 
HARD
The mean and the variance of five observations are 4 and 5.20, respectively. If three of the observations are 3,4 and 4; then the absolute value of the difference of the other two observations, is :
HARD
Let X be a random variable which takes values k with the probability kp, where k=1, 2, 3, 4 and p(0,1), then the standard deviation of X is
EASY
A random variable X has the following probability distribution:
X:12345PX: k22kk2k5k2
Then, PX>2 is equal to:
MEDIUM
A random variable X takes the values 0,1,2. Its mean is 1.2 if PX=0=0.3, then PX=1= 
HARD
Suppose A is 3×3 matrix consisting of integer entries that are chosen at random from the set -1000,-999,999,1000. Let P be the probability that either A2=-I or A is diagonal, where I is the 3×3 identity matrix. Then,
MEDIUM

A random variable X has the following probability distribution:

X=xi -2 -1 0 1 2
PX=xi 16 k 14 k 16

The variance of this random variable is

MEDIUM
If the variance of 10 natural numbers 1, 1, 1, , 1, k is less than 10, then the maximum possible integral value of k is ___________.
HARD
The sum of 100 observations and the sum of their squares are  400 & 2475, respectively. Later on, three observations 3, 4 & 5 were found to be incorrect. If the incorrect observations are omitted, then the variance of the remaining observations is
MEDIUM
The mean of five observations is 5 and their variance is 9.20. If three of the given five observations are 1, 3 and 8, then a ratio of other two observations is