The number of electrons delivered at the cathode, during electrolysis by a current of $1 \mathrm{ampere} \mathrm{in} 60 \mathrm{seconds}$ is (charge on electron $=1.60\times {10}^{-19}\mathrm{ }\mathrm{C}$)

In the electrochemical cell :$\mathrm{Zn}\left|{\mathrm{ZnSO}}_4(0.01\mathrm{M})\Vert {\mathrm{CuSO}}_4(1.0\mathrm{M})\right|\mathrm{Cu},$ the $\mathrm{emf}$ of this Daniel cell is ${\mathrm{E}}_1$. When the concentration of ${\mathrm{ZnSO}}_4$ is changed to $1.0 \mathrm{M}$ and that of ${\mathrm{CuSO}}_4$ changed to $0.01\mathrm{M}$, the $\mathrm{emf}$ changes to ${\mathrm{E}}_2$. From the followings, which one is the relationship between ${\mathrm{E}}_1$ and ${\mathrm{E}}_2?\left(\text{ Given, }\frac{\mathrm{RT}}{\mathrm{F}}=0.059\right)$.

The equivalent conductance of $\mathrm{NaCl}$ at concentration $\mathrm{C}$ and at infinite dilution are ${\mathrm{\lambda }}_{\mathrm{c}}$and ${\mathrm{\lambda }}_{\infty }$ respectively. The correct relationship between ${\mathrm{\lambda }}_{\mathrm{c}}$ and ${\mathrm{\lambda }}_{\infty }$ is given as (where, the constant $\mathrm{B}$ is positive)