The number of paramagnetic species among the following is ${\mathrm{B}}_2,{\mathrm{Li}}_2,{\mathrm{C}}_2,{\mathrm{C}}_2^{-},{\mathrm{O}}_2^{2-},{\mathrm{O}}_2^{+}$ and ${\mathrm{He}}_2^{+}$

The number of inter halogens from the following having square pyramidal structure is

${\mathrm{ClF}}_3, {\mathrm{IF}}_7, {\mathrm{BrF}}_5, {\mathrm{BrF}}_3, {\mathrm{I}}_2{\mathrm{Cl}}_6, {\mathrm{IF}}_5, \mathrm{ClF}, {\mathrm{ClF}}_5$

Given below are two statements : One is labelled as Assertion $\mathrm{A}$ and the other is labelled as Reason $\mathrm{R}$

Assertion $\mathrm{A}$ : Zero orbital overlap is an out of phase overlap.

Reason $\mathrm{R}$ : It results due to different orientation/ direction of approach of orbitals.

In the light of the above statements. Choose the correct answer from the options given below

Consider, ${\mathrm{PF}}_5,{\mathrm{BrF}}_5,{\mathrm{PCl}}_3,{\mathrm{SF}}_6,{\left[{\mathrm{ICl}}_4\right]}^{-},{\mathrm{ClF}}_3$ and ${\mathrm{IF}}_5$

Amongst the above molecule(s) ion(s), the number of molecule(s)/ion(s) having ${\mathrm{sp}}^3{\mathrm{d}}^2$ hybridisation is

Order of Covalent bond;

A. $\mathrm{KF}>\mathrm{KI}; \mathrm{LiF}>\mathrm{KF}$

B. $\mathrm{KF}<\mathrm{KI}; \mathrm{LiF}>\mathrm{KF}$

C. ${\mathrm{SnCl}}_4>{\mathrm{SnCl}}_2; \mathrm{CuCl}>\mathrm{NaCl}$

D. $\mathrm{LiF}>\mathrm{KF}; \mathrm{CuCl}>\mathrm{NaCl}$

E. $\mathrm{KF}<\mathrm{KI}; \mathrm{CuCl}>\mathrm{NaCl}$