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The number of ways in which $5$ red beads and $4$ yellow beads of different sizes can be made out to form a necklace so that no two yellow beads come together is

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Important Questions on Permutation and Combination

MEDIUM

Mathematics>Algebra>Permutation and Combination>Circular Permutations

f = (\begin{matrix} 1 \\ 3 \end{matrix} \begin{matrix} 2 \\ 4 \end{matrix} \begin{matrix} 3 \\ 6 \end{matrix} \begin{matrix} 4 \\ 7 \end{matrix} \begin{matrix} 5 \\ 5 \end{matrix} \begin{matrix} 6 \\ 1 \end{matrix}) \in S_{6}

then

f^{- 1}

MEDIUM

Mathematics>Algebra>Permutation and Combination>Circular Permutations

A round table conference is attended by

3

Indians,

3

Chinese,

3

Canadians and

2

Americans. Find the number of ways of arranging them at the round table so that the delegates belonging to same country sit together.

EASY

Mathematics>Algebra>Permutation and Combination>Circular Permutations

The number of ways, in which

5

girls and

7

boys can be seated at a round table so that no two girls sit together is

EASY

Mathematics>Algebra>Permutation and Combination>Circular Permutations

Find the number of ways of preparing a chain with

6

different coloured beads.

MEDIUM

Mathematics>Algebra>Permutation and Combination>Circular Permutations

20

persons are invited for a party. The number of ways in which they and the host can seated at a circular table, if two particular persons be seated on either side of the host is equal to

HARD

Mathematics>Algebra>Permutation and Combination>Circular Permutations

Five persons

A, B, C, D

and

E

are seated in a circular arrangement. If each of them is given a hat of one of the three colours red, blue and green, then the number of ways of distributing the hats such that the persons seated in adjacent seats get different coloured hats is

EASY

Mathematics>Algebra>Permutation and Combination>Circular Permutations

The number of ways

5

boys and

5

girls can be seated at a round table, so no two boys are adjacent is _____

EASY

Mathematics>Algebra>Permutation and Combination>Circular Permutations

The number of ways in which

6

men and

5

women can sit at a round table if no two women are to sit together is given by

EASY

Mathematics>Algebra>Permutation and Combination>Circular Permutations

The number of ways that a circle can be made out of

6

black and

4

white men standing on a ring, so that all the white men come together is

HARD

Mathematics>Algebra>Permutation and Combination>Circular Permutations

Six persons

A, B, C, D, E

and

F

are to be seated at a circular table facing towards the centre. Then the number of ways that can be done if

A

must have either

E

F

on his immediate right and

E

must have either

F

D

on his immediate right, is

MEDIUM

Mathematics>Algebra>Permutation and Combination>Circular Permutations

The number of ways in which

5

boys and

3

girls can be seated on a round table if a particular boy

B_{1}

and a particular girl

G_{1}

never sit adjacent to each other, is:

HARD

Mathematics>Algebra>Permutation and Combination>Circular Permutations

Six persons and

A, B, C, D, E & F

are to be seated at a circular table . The number of ways this can be done if

A

must have either

B

C

on his right and

B

must have either

C

D

on his right is

HARD

Mathematics>Algebra>Permutation and Combination>Circular Permutations

20

persons are to be seated around a circular table. Out of these

20

, two are brothers. Then number of arrangements in which there will be at least three persons between the brothers is

MEDIUM

Mathematics>Algebra>Permutation and Combination>Circular Permutations

In how many ways can 5 boys and 5 girls sit in a circle so that no two boys sit together ?

EASY

Mathematics>Algebra>Permutation and Combination>Circular Permutations

The number of different garlands, that can be formed using

3

flowers of first kind and

3

flowers of second kind, is

MEDIUM

Mathematics>Algebra>Permutation and Combination>Circular Permutations

The number of different necklaces that can be formed by using

2 n

identical diamonds and

3

different jewels -

HARD

Mathematics>Algebra>Permutation and Combination>Circular Permutations

The letters of the word "QUESTION" are arranged in a row at random. The probability that there are exactly two letters between Q and S is

EASY

Mathematics>Algebra>Permutation and Combination>Circular Permutations

The number of ways that 8 beads of different colures be string as a necklace, is

MEDIUM

Mathematics>Algebra>Permutation and Combination>Circular Permutations

If the total number of m elements subsets of the set A = {a₁, a₂, a₃, ... , a_n} is λ times the number of m elements subsets containing a₄, then n is

EASY

Mathematics>Algebra>Permutation and Combination>Circular Permutations

Eight Friends A, B, C, D, E, F, G and H are sitting around a circular table facing the centre not necessarily in the same order. B is second to the right of A. B is to the immediate left of H. D is second to right of B. C is fourth to left of H. F is an immediate neighbour of D. E is not an immediate neighbour of A.

Who is sitting exactly between E and A ?

The number of ways in which 5 red beads and 4 yellow beads of different sizes can be made out to form a necklace so that no two yellow beads come together is

Important Questions on Permutation and Combination

Learn and Prepare for any exam you want !

The number of ways in which $5$ red beads and $4$ yellow beads of different sizes can be made out to form a necklace so that no two yellow beads come together is