Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 1>Q 174

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IMPORTANT

Earn 100

The $pH$ of solution obtained by mixing $500 ml$ of $0.15 M H_{2} {SO}_{4}$ with $500 ml$ of $0.1 M NaOH$ is :

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Important Questions on Equilibrium

MEDIUM

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IMPORTANT

Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 1>Q 175

The

pH

value of

10^{- 4} M

NaOH

solution is:

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 1>Q 176

What will be the

pH

of a solution formed by mixing

40 {cm}^{3}

of

0.1 M HCl

with

10 {cm}^{3}

0.45 M

of

NaOH

?

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 1>Q 177

Which one has

pH = 12

?

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 1>Q 178

Equal volumes of

pH

of a solution

A

is

3

and another solution

B

having

pH = 2

are mixed, then resultant

pH

of the solution will be :

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 1>Q 179

On adding

0.04 g

solid

NaOH

to a

100 mL, \frac{M}{200} Ba (OH)_{2}

solution, determine change in

pH

:

EASY

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 1>Q 180

The

pH

value of

1 .0 \times 10^{- 8} M HCl

solution is less than

8

because

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 1>Q 181

The pH of $10^{- 7} M$ $NaOH$ is:

(Use $\log 2 = 0.3$ )

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IMPORTANT

Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 1>Q 182

The

pH

of

0.1 M {NH}_{4} OH (K_{b} = 1.8 \times 10^{- 5}) is

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