The particle of mass $m$ and charge $q$ will touch the infinitely large plate of uniform charge density $\sigma$, if its velocity $v$ is more than $\mathrm{\{}\mathrm{Given} \mathrm{that} \sigma q>0\}$

At a certain distance from a point charge, the electric field is $500 \mathrm{V} {\mathrm{m}}^{-1}$ and the potential is $3000 \mathrm{V}$. What is the distance?

The figure represents a square carrying charges $+q$, $+q$, $–q$ and $–q$ at its four corners as shown. Then the potential will be zero at points ($A$, $C$, $P$ and $Q$ are midpoints of sides)

Two equal positive charges are kept at points $A$ and $B$. The electric potential, while moving from $A$ to $B$ along the straight line

The potential difference between points $A$ and $B$ in the given uniform electric field is: