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The peak value of the following A.C. current, i=4sinωt+4sinωt+2π3 A is,

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Important Questions on Electromagnetic Induction

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D.C. ammeter is connected in a circuit through which an A.C. of 50 Hz is flowing. The ammeter will read
 
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A certain A.C voltage is represented by e=100sin(100πt+0.6). The peak value of A.C is
 
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The general equation for the instantaneous e.m.f. of a generator (frequency 50 cycles s-1), whose peak voltage is 200 V will be,
 
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An alternating voltage of e=1002sin(100t) V is connected to a condenser of 0.5 μF through an A.C. ammeter. The reading of the ammeter will be, 
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A hot wire ammeter reads 10 A in A.C. circuit. The peak value of the current is,
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A 40 Ω electric heater is connected to 200 V, 50 Hz mains supply. The peak value of electric current flowing in the circuit is approximately,
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The r.m.s value of an A.C. of 50 Hz  is 10 A. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be, 
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The r.m.s. value of induced voltage in a coil of 50 turns each of area 30 cm2 rotating at 1000 r.p.m. about an axis at right angles to magnetic field is B=5×10-4 Wb m-2,