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The plot of velocity (v) versus displacement (x) of a particle executing simple harmonic motion is shown in figure. The time period of oscillation of particle is
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Important Questions on Oscillations

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A 1.00×1020 kg particle is vibrating with simple harmonic motion with a period of 1.00×105 sec and a maximum speed of 1.00×103 m s-1. The maximum displacement of the particle is
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The equation of an SHM with amplitude A and angular frequency ω in which all the distances are measured from one extreme position and time is taken to be zero at the other extreme position is
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A body oscillates with SHM according to the equation x=(5.0 m)cos2πrads-1t+π/4 At t=1.5 s, its acceleration is
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The period of a particle executing SHM is 8 s. At t=0, it is at the mean position. The ratio of the distances covered by the particle in the 1st second to the 2nd second is
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Figure shows the position-time graph of an object in SHM. The correct equation representing this motion is
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A particle executes SHM and its position varies with time as x=Asinωt. Its average speed during its motion from mean position to mid-point of mean and extreme position is
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A particle is executing SHM and its velocity v is related to its position (x) as v2+ax2=b, where a and b are positive constants. The frequency of oscillation of particle is
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A particle executes SHM according to equation x=10( cm)cos2πt+π2, where t is in second. The magnitude of the velocity of the particle at t=16 s will be