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The position of a particle moving on a straight line under the action of a force is given as x=50t-5t2. Here, x is in metre and t is in second. If mass of the particle is 2 kg, the work done by the force acting on the particle in first 5 s is

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Important Questions on Work, Energy and Power

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JEE Main/Advance
IMPORTANT
In a vertical spring mass system, a block of mass m is initially at rest when there is no extension. Now if the mass is released suddenly, then the maximum elongation in the spring is
EASY
JEE Main/Advance
IMPORTANT
A particle of mass m initially at rest. A variable force acts on the particle f=kx2 where k is a constant and x is the displacement. Find the work done by the force f when the speed of particle is v.
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JEE Main/Advance
IMPORTANT
Potential energy is defined
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JEE Main/Advance
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The PE of a 2 kg particle, free to move along x-axis is given by Vx=x33-x22J. The total mechanical energy of the particle is 4 J. Maximum speed in ms-1 is
MEDIUM
JEE Main/Advance
IMPORTANT
On a particle placed at origin, a variable force F=-ax (where a is a positive constant) is applied. If U(0)=0, then the graph between PE of particle U(x) and x is best represented by
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JEE Main/Advance
IMPORTANT

A rectangular block is moving along a frictionless path, when it encounters the circular loop as shown. The block passes points 1,2,3,4,1 before returning to the horizontal tracks. At point 3

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JEE Main/Advance
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Figure shows a body A at the top of a frictionless hemispherical inverted bowl of radius R. If the body starts slipping from the highest point, then the horizontal distance between the point where it leaves contact with sphere and the point at which the body was placed is

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JEE Main/Advance
IMPORTANT
A ball suspended by a thread swings in a vertical plane so that its acceleration in the extreme position and lowest position are equal in magnitude. The angle θof the deflection in extreme position will be