A particle of mass m moves along a curve, y = x 2 . When the particle has x - coordinate as 1 2 m and x - component of velocity as 4 m s - 1 , then

the magnitude of velocity at that instant is, 4 2 m s - 1 .

the magnitude of velocity at that instant is, 2 2 m s - 1 .

The velocity of a particle moving in the positive direction of x - axis varies as v = 10 x . Assuming that at t = 0 , particle was at x = 0 ,

the acceleration of the particle is 50 m s - 2 .

the initial velocity of the particle is 2 . 5 m s - 1 .

the acceleration of the particle is 2 . 5 m s - 2 .

EASY

JEE Main

IMPORTANT

Earn 100

The position vector of a particle is given as $\vec{r} = (t^{2} - 4 t + 6) \hat{i} + (t^{2}) \hat{j}$ . The time after which the velocity vector and the acceleration vector become perpendicular to each other, is equal to

50% studentsanswered this correctly

Important Questions on Motion in One Dimension

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Mechanics I JEE Main & Advanced>Chapter 4 - Motion in One Dimension>DPP>Q 10

A particle of mass

m

moves along a curve,

y = x^{2}

. When the particle has

x -

coordinate as

\frac{1}{2} m

and

x -

component of velocity as

4 m s^{- 1}

, then

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Mechanics I JEE Main & Advanced>Chapter 4 - Motion in One Dimension>DPP>Q 11

The velocity of a particle moving in the positive direction of

x -

axis varies as

v = 10 \sqrt{x}

. Assuming that at

t = 0

, particle was at

x = 0

HARD

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Mechanics I JEE Main & Advanced>Chapter 4 - Motion in One Dimension>DPP>Q 12

A particle moves along

x -

axis such that its position varies with time as

x = 50 t - 5 t^{2}

. Select the correct alternative(s).

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Mechanics I JEE Main & Advanced>Chapter 4 - Motion in One Dimension>DPP>Q 1

A particle is moving along a straight line with a constant acceleration of

- 4 m s^{- 2}

. It passes through a point

A

on the line with a velocity of

+ 8 m s^{- 1}

at some moment. The distance traveled by the particle in

5 \sec

after that moment will be

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Mechanics I JEE Main & Advanced>Chapter 4 - Motion in One Dimension>DPP>Q 2

A driver having a definite reaction time is capable of stopping his car over a distance of

30 m

on seeing a red traffic signal, when the speed of the car is

72 km h^{- 1}

and over a distance of

10 m

, when the speed is

36 km h^{- 1}

. Find the distance over which he can stop the car if it was running at a speed of

54 km h^{- 1}

. Assume that his reaction time and the deceleration of the car remains the same in all three cases.

EASY

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Mechanics I JEE Main & Advanced>Chapter 4 - Motion in One Dimension>DPP>Q 3

A particle experiences a constant acceleration for

20 s

after starting from rest. If it travels a distance

S_{1}

in the first

10 s

and a distance

S_{2}

in the next

10 s

, then

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Mechanics I JEE Main & Advanced>Chapter 4 - Motion in One Dimension>DPP>Q 4

A body is moving from rest under constant acceleration. Let

S_{1}

be the displacement in the first

(p - 1) \sec

and

S_{2}

be the displacement in the first

p \sec

. The displacement in

{(p^{2} - p + 1)}^{th} \sec

will be

MEDIUM

JEE Main

IMPORTANT

Chapterwise/Topicwise Daily Practice Problems (DPP) Mechanics I JEE Main & Advanced>Chapter 4 - Motion in One Dimension>DPP>Q 5

A particle travels

10 m

in the first

5 \sec

and

10 m

in the next

3 \sec

. Assuming constant acceleration, what is the distance traveled in the next

2 \sec

The position vector of a particle is given as r→=t2-4t+6 i^+t2 j^. The time after which the velocity vector and the acceleration vector become perpendicular to each other, is equal to

Important Questions on Motion in One Dimension

Learn and Prepare for any exam you want !

The position vector of a particle is given as $\vec{r} = (t^{2} - 4 t + 6) \hat{i} + (t^{2}) \hat{j}$ . The time after which the velocity vector and the acceleration vector become perpendicular to each other, is equal to