MEDIUM
11th CBSE
IMPORTANT
Earn 100

The potential energy function for a particle executing linear simple harmonic motion is given by V(x)=kx22, where k is the force constant of the oscillator. For k=0.5 N m-1, the graph of V(x) versus x is shown in Fig. Show that a particle of total energy 1 J moving under this potential must ‘turn back’ when it reaches x=± 2 m.

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Important Points to Remember in Chapter -1 - Work, Energy and Power from NCERT PHYSICS PART 1 TEXTBOOK FOR CLASS XI Solutions

1. Dot product of two vector:

(i) Dot product or scalar product of two vectors A and B is defined as A.B= A×B×cosθ, where θ is the angle between A and B

(ii) A= Axi^+Ayj^+Azk^ and B= Bxi^+Byj^+Bzk^ then, A.B= AxBx+AyBy+AzBz

(iii) Work done by a constant force, W= F.s

(iv) Work done by a variable force dW= F.ds

2. Relation between kinetic energy and momentum: 

Relation between momentum and kinetic energy, KE= P22m and P= 2m×KE, where P is linear momentum

3. Potential energy:

(i) Potential energy (U) and force are related as, U1U2dU= -r1r2F.dr i.e., U2-U1= -r1r2F.dr=-W where W is the work done by the conservative force.

(ii) Conservative force can be found from potential energy using the equation, F(x)= -dUdx

4. Work energy theorem:

According to work-energy theorem, the net work done on a body is equal to the change in the kinetic energy, Wnet= ΔKE

5. Power:

(i) Power is the rate of work done, P= dWdt

(ii) The average power delivered by an agent is given by Pav= Wt

(iii) Instantaneous power, P= FdSdt= FdSdt= F.V

6. Conservation of energy:

(i) According to conservation of mechanical energy, the total mechanical energy of an isolated system is conserved if the internal forces are conservative.

7. Collisions:

(i) The total momentum of a system remains constant during a collision.

(ii) Gravitational force and spring force are always non-impulsive during collision.

(iii) Total energy is conserved in an elastic collision.

(iv) The energy lost is maximum in a perfectly inelastic collision.

(v) The two equations which we can use in a collision are: m1u1+m2u2= m1v1+m2v2 and e(u1-u2)= v2-v1.

(vi) e is the coefficient of restitution. It is 1 for elastic collision, 0 for perfectly inelastic collision and for inelastic collision it will be between 0 and 1.