EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Complex Numbers>KEAM 2020>Q 5

HARD

KEAM

IMPORTANT

Earn 100

The principal argument of the complex number $z = \frac{1 + \sin π - i \cos π}{1 + \sin π + i \cos π}$ is

100% studentsanswered this correctly

Important Questions on Complex Numbers

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Complex Numbers>KEAM 2019>Q 6

If

z

is a normal root of

\sqrt[7]{- 1}

then

z^{85} + z^{142} + z^{191}

is.

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Complex Numbers>KEAM 2019>Q 7

If

z_{1} = 5 y^{2} - 3 - 8 i x, z_{2} = 4 y^{2} - 16 i

and

z_{1} = {\bar{z}}_{2}

then

z = x + i y

is equal to

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Complex Numbers>KEAM 2019>Q 8

The value of

(1 + i)^{5} \times (1 - i)^{5}

is

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Complex Numbers>KEAM 2018>Q 9

The value of

{(i^{18} + {(\frac{1}{i})}^{25})}^{3}

is equal to

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Complex Numbers>KEAM 2018>Q 10

The modulus of

\frac{1 + i}{1 - i} - \frac{1 - i}{1 + i}

is

MEDIUM

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Complex Numbers>KEAM 2018>Q 11

If

a

and

b

are real numbers and

{(a + i b)}^{11} = 1 + 3 i

,

then

{(b + i a)}^{11}

is equal to

MEDIUM

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Complex Numbers>KEAM 2018>Q 12

If

z_{1} = 2 - i

and

z_{2} = 1 + i

,

then

|\frac{z_{1} + z_{2} + 1}{z_{1} - z_{2} + i}|

is

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 14 - Complex Numbers>KEAM 2020>Q 13

Simplified form of

\frac{10 i}{1 + 2 i}

is equal to