Fill in the blank boxes 4 8 2 × □ □ 9 □ 8

Given, 4 8 2 × □ □ 9 □ 8 When we multiply 4 with 2 we will get 8 . So, number comes in first box is 4 . Product of 4 × 8 = 32 . So, in answer in first box 2 will come and 3 will be carry forward to hundred place . Now, 4 × 4 = 16 and add carry forward 3 = 16 + 3 = 19 . So, in answer digit comes in second box from right is 1 Thus, the answer is 4 8 2 × 4 1 9 2 8

Fill in the blank boxes 8 5 3 × □ □ □ 5 □ 9 5 □ □ 1 × □ □ □ □ 9

Given, 8 5 3 × □ □ □ 5 □ 9 5 □ □ 1 × □ □ □ □ 9 Star with the ones place When we multiply 3 with 3 we will get 9 . So, number comes in first box at ones place is 3 . Product of 5 × 3 = 15 . So, in answer in first box in first line from the right 5 will come and 1 will be carry forward to hundred place . Now, 8 × 3 = 24 and add carry forward 1 = 24 + 1 = 25 . So, in answer digit comes in second box of first line from right is 2 Second line When we multiply 7 × 3 = 21 . So, 1 is already written from right and 2 will be carry forward to tens place. Now, 7 × 5 = 35 add 2 carry = 35 + 2 = 37 . So in first box 7 will come and 3 carry forward to hundred place. Now, 7 × 8 = 56 add 3 carry forward 56 + 3 = 59 . So, in second box 9 will come. Now add the numbers. Thus, the answer is 8 5 3 × 7 3 2 5 5 9 5 9 7 1 × 6 2 2 6 9

Fill in the blank boxes 3 □ 4 □ × 2 6 2 7 8 □ 6 □ □ □ 5 □ × □ □ □ □ × × □ □ □ □ 0 □ 6

Given, 3 □ 4 □ × 2 6 2 7 8 □ 6 □ □ □ 5 □ × □ □ □ □ × × □ □ □ □ 0 □ 6 Star with the ones place When we multiply 3 with 2 we will get 6 . Product of 4 × 2 = 8 . 9 × 2 = 18 . So, 8 will comes at hundred place and add carry forward 1 . Second line When we multiply 6 × 3 = 18 . So, 8 will come at empty place and 1 will be carry forward to tens place. Now, 6 × 4 = 24 add 1 carry = 24 + 1 = 25 . So in the empty space 5 will come and 2 carry forward to hundred place. Now, 6 × 9 = 54 add 2 carry forward 54 + 2 = 56 . So, in second box 6 will come and 5 will be carry forward. Then, 6 × 3 = 18 and add 5 carry forward 18 + 5 = 23 Third line 2 × 3 = 6 2 × 4 = 8 9 × 2 = 18 3 × 2 = 6 ( 6 + 1 = 7 ) Now add the numbers. Thus, the answer is 3 9 4 3 × 2 6 2 7 8 8 6 2 3 6 5 8 × 7 8 8 6 × × 1 0 3 3 0 6 6

E M B I B E

New Global Mathematics - 6>Chapter 3 - Operations on Whole Numbers>EXERCISE 3.3>Q 7

HARD

6th CBSE

IMPORTANT

Earn 100

The product of two $2 -$ digit numbers is $1376 .$ If the product of their unit's digits is $6$ and that of ten's digits is $12 .$ Find the numbers.

Important Questions on Operations on Whole Numbers

HARD

6th CBSE

IMPORTANT

New Global Mathematics - 6>Chapter 3 - Operations on Whole Numbers>EXERCISE 3.3>Q 8

A dealer purchased $236$ wheat bags. If the cost of each bag is $₹ 1888$ , determine the cost of all bags together.

MEDIUM

6th CBSE

IMPORTANT

New Global Mathematics - 6>Chapter 3 - Operations on Whole Numbers>EXERCISE 3.3>Q 9

Fill in the blank boxes

$\begin{matrix} 4 & 8 & 2 \\ \times & □ \\ □ & 9 & □ & 8 \end{matrix}$

HARD

6th CBSE

IMPORTANT

New Global Mathematics - 6>Chapter 3 - Operations on Whole Numbers>EXERCISE 3.3>Q 9

Fill in the blank boxes

$\begin{matrix} 8 & 5 & 3 \\ \times & □ & □ \\ □ & 5 & □ & 9 \\ 5 & □ & □ & 1 & \times \\ □ & □ & □ & □ & 9 \end{matrix}$

HARD

6th CBSE

IMPORTANT

New Global Mathematics - 6>Chapter 3 - Operations on Whole Numbers>EXERCISE 3.3>Q 9

Fill in the blank boxes

$\begin{matrix} 3 & □ & 4 & □ \\ \times & 2 & 6 & 2 \\ 7 & 8 & □ & 6 \\ □ & □ & □ & 5 & □ & \times \\ □ & □ & □ & □ & \times & \times \\ □ & □ & □ & □ & 0 & □ & 6 \end{matrix}$