Under what condition the order of the reaction, 2 H I → H 2 g + I 2 g , is zero

At high partial pressure of H I

At high partial pressure of H 2

At high partial pressure of I 2

Under what condition the order of the reaction, 2 H I → H 2 g + I 2 g , is zero

At high partial pressure of H I

At high partial pressure of H 2

At high partial pressure of I 2

E M B I B E

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 17 - Chemical Kinetics>KEAM 2020>Q 3

MEDIUM

KEAM

IMPORTANT

Earn 100

The rate constant of a first order reaction is $231 \times 10^{- 5} s^{- 1}$ . How long will $4 g$ of this reactant reduce to $2 g$ ?

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Important Questions on Chemical Kinetics

HARD

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 17 - Chemical Kinetics>KEAM 2018>Q 4

The data given below are for the reaction of

A

and

D_{2}

to form product at

295 K

. Find the correct rate expression for this reaction

$\frac{D_{2}}{m o l L^{- 1}}$	$\frac{A}{m o l L^{- 1}}$	$\frac{I n i t i a l r a t e}{m o l L^{- 1} s^{- 1}}$
$0.05$	$0.05$	$1 \times 10^{- 3}$
$0.15$	$0.05$	$3 \times 10^{- 3}$
$0.05$	$0.15$	$9 \times 10^{- 3}$

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 17 - Chemical Kinetics>KEAM 2018>Q 5

Under what condition the order of the reaction,

2 H I \to H_{2} (g) + I_{2} (g),

is zero

MEDIUM

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 17 - Chemical Kinetics>KEAM 2020>Q 6

An endothermic reaction

A \to B

has an activation energy of

13 kJ {mol}^{- 1}

and the enthalpy change for the reaction is

2 kJ {mol}^{- 1}

. The activation energy of the reaction

B \to A

is

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The rate constant of a first order reaction is 231×10-5 s-1. How long will 4 g of this reactant reduce to 2 g?

Important Questions on Chemical Kinetics

Learn and Prepare for any exam you want !

The rate constant of a first order reaction is $231 \times 10^{- 5} s^{- 1}$ . How long will $4 g$ of this reactant reduce to $2 g$ ?