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The ratio of the frequencies of the long wavelength limits of the Brackett and Pfund series of hydrogen is
 

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Important Questions on Atoms, Molecules and Nuclei

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The first line of the Balmer series has wavelength 6563 Å. What will be the wavelength of the first member of the Lyman series?
 
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If series limit of Balmer series is 6400 Å, then series limit of Paschen series will be
 
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An electron jumps from 3rd to  2nd  orbit of hydrogen atom. Taking the Rydberg constant as 107 m-1, what will be the frequency of the radiation emitted? c=3×108 m s-1
 
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The wavelength of emitted radiation in terms of R (the Rydberg constant) is λ=365R. The electron jumps from
 
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Shortest wavelength in the Lyman series is 912 Å.The longest wavelength in this series will be
 
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The wavelength of the first line of Lyman series of hydrogen is 121.6 nm. The wavelength of the second member of Balmer series is
 
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Wavelength of radiations emitted when an electron jumps from a state A to state C is 2000 Å and it is 6000 Å when the electron jumps from the state B to state C, wavelength of the radiations emitted when an electron jumps from state A to B will be
 
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Let X and Z be the frequencies limit of Lyman series and Balmer series respectively. If Y is the frequency of first line of Lyman series, then