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The reactance of a capacitor in an A.C. circuit is 10 Ω. If the frequency of A.C. is doubled, its reactance will become, 
 

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Important Questions on Electromagnetic Induction

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The inductive reactance of a coil is 1000 Ω. If its inductance and the frequency of A.C. supply are both doubled, then the reactance will become,
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In a series A.C. circuit, R=100 Ω, XL=300 Ω and XC=200 Ω. The phase difference between the applied e.m.f. and the current will be,
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The e.m.f. of A.C. source in L-C-R circuit shown in the figure is,

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An inductive coil has a resistance of 100 Ω when an A.C. source of frequency 1000 Hz is applied to the coil, the applied voltage leads the current by 45°. The inductance of the
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A series LCR circuit has the following values R=20 Ω, XL=10 Ω, E=50 V (RMS) at ω=400 rad s-1. Current 2 A leads the applied voltage. The value of the capacitative reactance XC is, 
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When 100 V D.C. flows in a solenoid, the current is 1.0 A. When 100 V A.C. flows, the current drops to 0.5 A. If the frequency of A.C. be 50 Hz, then the impedance and the inductance of the solenoid are, 
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It is found that the current in the circuit is 0.50 A with D.C. source and 0.40 A with A.C. source. The voltage E for  D.C. is 120 V and for A.C. is 120 V. The frequency of A.C. source is 60 Hz. The inductance of the circuit is, 
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A variable capacitor and an inductive coil with negligible resistance are connected in series to an A.C. voltage of value 100 V. The current in the circuit is 5 A. When the capacitor decreases to half of its value, the current becomes 10 A. The voltage across the capacitor in first case is,