Match List - I with List - II : List - I (Metal ion) List - II (Group in Qualitative analysis) (a) Mn 2 + (i) Group - III (b) As 3 + (ii) Group - IIA (c) Cu 2 + (iii) Group - IV (d) Al 3 + (iv) Group - IIB Choose the most appropriate answer from the options given below :

(a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)

(a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)

(a)-(i), (b)-(iv), (c)-(ii), (d)-(iii)

(a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)

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The reaction of $Pb {({NO}_{3})}_{2}$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration. The dissolution of the precipitate is due to the formation of

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Important Questions on Theoretical Principles of Experimental Chemistry

EASY

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

To an aqueous solution containing ions such as

{Al}^{3 +}, {Zn}^{2 +}, {Ca}^{2 +}, {Fe}^{3 +}, {Ni}^{2 +}, {Ba}^{2 +}

and

{Cu}^{2 +}

was added

conc . HCl

, followed by

H_{2} S

. The total number of cations precipitated during this reaction is/are :

EASY

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

Which one of the following compounds is not a yellow colored compound ?

MEDIUM

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

{PbO}_{2}

is obtained from

EASY

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

Match List - I with List - II :

	List - I (Metal ion)		List - II (Group in Qualitative analysis)
(a)	${Mn}^{2 +}$	(i)	Group - III
(b)	${As}^{3 +}$	(ii)	Group - IIA
(c)	${Cu}^{2 +}$	(iii)	Group - IV
(d)	${Al}^{3 +}$	(iv)	Group - IIB

Choose the most appropriate answer from the options given below :

HARD

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

A solution containing a group

- IV

cation gives a precipitate on passing

H_{2} S .

A solution of this precipitate in dil.

HCl

produces a white precipitate with

NaOH

solution and bluish-white precipitate with basic potassium ferrocyanide. The cation is

MEDIUM

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

Consider the sulphides

HgS, PbS, CuS, {Sb}_{2} S_{3}, {As}_{2} S_{3}

and

CdS .

Number of these sulphides soluble in

50 % {HNO}_{3}

is ___________ .

MEDIUM

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

When

H_{2} S

gas is passed into a mixture of

{Mn}^{2 +}, {Ni}^{2 +}, {Cu}^{2 +}

and

{Hg}^{2 +}

ion in an acidified aqueous solution, the precipitates formed are

MEDIUM

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

{Fe}^{3 +}

cation gives a prussian blue precipitate on addition of potassium ferrocyanide solution due to the formation of

MEDIUM

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

When

H_{2} S

gas is passed through a hot acidic aqueous solution containing

{Al}^{3 +}, {Cu}^{2 +}, {Pb}^{2 +}

and

{Ni}^{2 +},

a precipitate is formed which consists of

MEDIUM

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

For the following Assertion and Reason, the correct option is

Assertion (A) : When $Cu$ (II) and sulphide ions are mixed, they react together extremely quickly to give a solid.

Reason (R) : The equilibrium constant of ${Cu}^{2 +} (aq) + S^{2 -} (aq) ⇌ CuS (s)$ is high because the solubility product is low.

EASY

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

The Nessler's reagent contains

MEDIUM

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

The incorrect statement is:

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Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

Question Image

What are $A, B, C, D$ ?

HARD

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

Acidic ferric chloride solution on treatment with excess of potassium ferrocyanide gives a Prussian blue coloured colloidal species. It is:

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Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

During the qualitative analysis of salt with cation

y^{2 +}

, addition of a reagent

(X)

to alkaline solution of the salt gives a bright red precipitate. The reagent

(X)

and the cation

(y^{2 +})

present respectively are :

EASY

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

Mercurous ion

({Hg}_{2}^{2 +})

gives white precipitate on reacting with

MEDIUM

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

The pair(s) of ions where BOTH the ions are precipitated upon passing

H_{2} S

gas in presence of dilute

HCl

, is (are)

MEDIUM

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

Copper sulphate solution reacts with

KCN

to give

MEDIUM

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

Upon treatment with ammoniacal

H_{2} S

, the metal ion that precipitates as a sulphide is

MEDIUM

Chemistry>Inorganic Chemistry>Theoretical Principles of Experimental Chemistry>Systematic Analysis of Cationic Radicals

The cation that will not be precipitated by

H_{2} S

in the presence of dil HCl is:

The reaction of PbNO32 and NaCl in water produces a precipitate that dissolves upon the addition of HCl of appropriate concentration. The dissolution of the precipitate is due to the formation of

Important Questions on Theoretical Principles of Experimental Chemistry

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The reaction of $Pb {({NO}_{3})}_{2}$ and $NaCl$ in water produces a precipitate that dissolves upon the addition of $HCl$ of appropriate concentration. The dissolution of the precipitate is due to the formation of