EASY
12th Odisha Board
IMPORTANT
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The relation between current density (J), conductivity (σ) and electric field strength (E) is =σE .

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Important Questions on Electric Current

EASY
12th Odisha Board
IMPORTANT
Bureau's Higher Secondary Physics Class 12>Chapter 5 - Electric Current>MODEL QUESTIONS>Q 7
The expression for conductivity in terms of J and E is _____.
EASY
12th Odisha Board
IMPORTANT
Bureau's Higher Secondary Physics Class 12>Chapter 5 - Electric Current>MODEL QUESTIONS>Q 1
Correct the sentence - The resistance of a metallic conductor decreases with rise in temperature.
EASY
12th Odisha Board
IMPORTANT
Bureau's Higher Secondary Physics Class 12>Chapter 5 - Electric Current>MODEL QUESTIONS>Q 2
Correct the sentence - Holes are charge carriers in n-type germanium.
EASY
12th Odisha Board
IMPORTANT
Bureau's Higher Secondary Physics Class 12>Chapter 5 - Electric Current>MODEL QUESTIONS>Q 3
Correct the sentence - Volt=Ampere/ohm
EASY
12th Odisha Board
IMPORTANT
Bureau's Higher Secondary Physics Class 12>Chapter 5 - Electric Current>MODEL QUESTIONS>Q 4
Correct the sentence - Electric current is a vector quantity.
EASY
12th Odisha Board
IMPORTANT
Bureau's Higher Secondary Physics Class 12>Chapter 5 - Electric Current>MODEL QUESTIONS>Q 5
Correct the sentence - The relation between current density j→, conductivity σ and electric field E→ is E→=σ.j→
EASY
12th Odisha Board
IMPORTANT
Bureau's Higher Secondary Physics Class 12>Chapter 5 - Electric Current>MODEL QUESTIONS>Q 6
Correct the sentence - Dimension of electric potential difference is ML2T3A-1
EASY
12th Odisha Board
IMPORTANT
Bureau's Higher Secondary Physics Class 12>Chapter 5 - Electric Current>MODEL QUESTIONS>Q 7
Correct the sentence - Two copper wires have their radius in the ratio 2:3, their resistance shall be in the ratio 4:9 .