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The relative lowering of vapour pressure is equal to the mole fraction of the non-volatile solute. This statement was given by:

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Important Questions on Solutions

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The vapour pressure of a solution having solid as solute and liquid as solvent is:
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One mole of non-volatile solute is dissolved in two mole of water. The vapour pressure of the solution relative to that of water is:
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The vapour pressure of a dilute aqueous solution of Glucose is 750 mm of mercury at 373K. The mole fraction of solute is -
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The vapour pressure of water at room temperature is 23.8 mm of Hg. The vapour pressure of an aqueous solution of sucrose with mole fraction 0.1 is equal to:

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The vapour pressure of pure liquid A is 10 torr and at the same temperature when 1 g of B solid is dissolved in 20 g of A, its vapour pressure is reduced to 9.0 torr. If the molecular mass of A is 200 amu, then the molecular mass of B is:
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The boiling point of C6H6, CH3OH, C6H5NH2 and C6H5NO2 are 80°C, 65°C, 184°C and 212°C, respectively. Which one will show the highest vapour pressure at room temperature?
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If Raoult's law is obeyed, the vapour pressure of the solvent in a solution is directly proportional to:
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The vapour pressure of a pure liquid A is 70 torr at 27 0C. It forms an ideal solution with another liquid B. The mole fraction of B is 0.2 and the total vapour pressure of the solution is 84 torr at 27 0C. The vapour pressure of pure liquid B at 27 0C is ______.