EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 15 - Binomial Theorem>KEAM 2018>Q 11

EASY

KEAM

IMPORTANT

Earn 100

The remainder when $2^{2000}$ is divided by $17$ is

66.67% studentsanswered this correctly

Important Questions on Binomial Theorem

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 15 - Binomial Theorem>KEAM 2018>Q 12

({}^{7}{C_{0}} + {}^{7}{C_{1}}) + ({}^{7}{C_{2} + {}^{7}{C_{3}}}) + \dots + ({}^{7}{C_{6} + {}^{7}{C_{7}}}) =

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 15 - Binomial Theorem>KEAM 2020>Q 13

The middle term in the expansion of

{(1 + \frac{1}{5})}^{20}

is

HARD

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 15 - Binomial Theorem>KEAM 2019>Q 14

The third term in the expansion of

{(\frac{1}{x} + x^{\log_{10} x})}^{5}, x > 1

is

1000,

then

x

equals.

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 15 - Binomial Theorem>KEAM 2019>Q 15

The coefficient of

x^{13}

in the expansion of

{(1 - x)}^{5} {(1 + x + x^{2} + x^{3})}^{4}

is

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 15 - Binomial Theorem>KEAM 2018>Q 16

The coefficient of

x^{5}

in the expansion of

{(x + 3)}^{8}

is

EASY

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 15 - Binomial Theorem>KEAM 2018>Q 17

The coefficient of

x

in the expansion of

(1 - 3 x + 7 x^{2}) {(1 - x)}^{16}

is

MEDIUM

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 15 - Binomial Theorem>KEAM 2019>Q 18

If

{}^{n}C_{r - 1} = 10, {}^{n}C_{r} = 45

and

{}^{n}C_{r + 1} = 120,

then

r

equals

HARD

KEAM

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 15 - Binomial Theorem>KEAM 2018>Q 19

Sum of last

30

coefficents in the binomial expansion of

{(1 + x)}^{59}

is