HARD
12th Odisha Board
IMPORTANT
Earn 100

The resistance of 0.5 N solution of an electrolyte in a cell was found to be 45 ohm. Calculate the equivalent conductance of the solution if the electrodes in a cell are 2.2 cm apart and have an area of 3.8 sq.cm .

Important Questions on Electrochemistry

HARD
12th Odisha Board
IMPORTANT
State and explain Faraday’s laws of electrolysis. 0.2015 gm of copper were deposited by a current of 0.25 ampere in 45 minutes. What is the E.C.E. of the copper?
HARD
12th Odisha Board
IMPORTANT
Describe the construction and working of Daniell cell.
HARD
12th Odisha Board
IMPORTANT

The following reaction occurs in a cell Zn(s)+Co2+Co(s)+Zn2+.

Write the electrode reaction and find out the e.m.f. cell, given

ZnZn2+, E0=0.76 VCoCo2+, E0=0.28 V

HARD
12th Odisha Board
IMPORTANT
What are the difference between ionisation and electrolysis? What are strong and weak electrolytes, discuss with examples.
HARD
12th Odisha Board
IMPORTANT
What is the difference between e.m.f. and potential difference?
HARD
12th Odisha Board
IMPORTANT
Give two applications of electrolysis.
HARD
12th Odisha Board
IMPORTANT

Define equivalent and molar conductance. Give their relationship with specific conductance. How does equivalent conductance vary with increase in temperature?

How many atoms of calcium will be deposited from fused CaCl2 by a current of 25 milliamperes passes for 60 seconds?

HARD
12th Odisha Board
IMPORTANT
State and explain equivalent conductance and specific conductance. Calculate the mass of silver deposited when a current of one ampere is passed through AgNO3 solution for hour. The electrochemical equivalent of silver is 1.21×103