Name: Bohr's Model for the Hydrogen Atom
Uploaded: 2019-07-19
Duration: 4 min 50 s
Description: Why don't the revolving electrons in an atom not collide with any protons? Why do different elements emit a different colour? Let's study Bohr's hydrogen ato...

Question

The short wavelength limit for the Lyman series of the hydrogen spectrum is $913.4 A^{0}$ . Calculate the short wavelength limit for Balmer series of hydrogen spectrum.

Accepted Answer

Given, shortest wavelength of Lyman series is, $λ_{1} = 913.4 A^{0}$
For the shortest wavelength, the energy difference should be maximum. This means the electron should drop from infinity to $1^{s t}$ orbit for Lyman series and $2^{n d}$ orbit for Balmer series.
$\Rightarrow \frac{1}{λ_{1}} = R (\frac{1}{1^{2}} - \frac{1}{\infty}) = R$ .....(1)
Shortest wavelength of $(λ_{2})$ of Balmer series, say, is $λ_{2}$ .

$\Rightarrow \frac{1}{λ_{2}} = R (\frac{1}{2^{2}} - \frac{1}{\infty}) = \frac{R}{4}$ .....(2)
Dividing the equation, we get, $\frac{λ_{2}}{λ_{1}} = R \times \frac{4}{R}$

$\Rightarrow λ_{2} = 4 λ_{1} = 4 \times 913.4 = 3653.6 A^{0}$

The short wavelength limit for the Lyman series of the hydrogen spectrum is $913.4 A^{0}$ . Calculate the short wavelength limit for Balmer series of hydrogen spectrum.

Important Questions on Atoms

Learn and Prepare for any exam you want !

The short wavelength limit for the Lyman series of the hydrogen spectrum is 913.4 A0. Calculate the short wavelength limit for Balmer series of hydrogen spectrum.

Important Questions on Atoms

Learn and Prepare for any exam you want !

The short wavelength limit for the Lyman series of the hydrogen spectrum is $913.4 A^{0}$ . Calculate the short wavelength limit for Balmer series of hydrogen spectrum.