EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 6 September 2020 Shift 1>Q 64

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IMPORTANT

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The shortest distance between the lines $\frac{x - 1}{0} = \frac{y + 1}{- 1} = \frac{z}{1}$ and $x + y + z + 1 = 0, 2 x - y + z + 3 = 0$ is

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Important Questions on Three Dimensional Geometry

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JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 6 September 2020 Shift 2>Q 65

A plane

P

meets the coordinate axes at

A, B

and

C

respectively. The centroid of

∆ ABC

is given to be

(1, 1, 2)

. Then the equation of the line through this centroid and perpendicular to the plane

P

is :

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JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 7th January 2020 Shift 1>Q 66

Let

P

be a plane passing through the points

(2, 1, 0), (4, 1, 1)

and

(5, 0, 1)

and

R

be any point

(2, 1, 6)

.Then the image of

R

in the plane

P

is

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 7th January 2020 Shift 2>Q 67

If the foot of the perpendicular drawn from the point

(1, 0, 3)

on a line passing through

(α, 7,1)

is

(\frac{5}{3}, \frac{7}{3}, \frac{17}{3})

, then

α

is equal to

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 8th January 2020 Shift 1>Q 68

The shortest distance between the lines

\frac{x - 3}{3} = \frac{y - 8}{- 1} = \frac{z - 3}{1}

and

\frac{x + 3}{- 3} = \frac{y + 7}{2} = \frac{z - 6}{4}

is

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 8th January 2020 Shift 2>Q 69

The mirror image of the point

(1, 2, 3)

in a plane is

(- \frac{7}{3}, - \frac{4}{3}, - \frac{1}{3}) .

Which of the following points lies on this plane?

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 9th January 2020 Shift 2>Q 70

If the distance between the plane,

23 x - 10 y - 2 z + 48 = 0

and the plane containing the lines

\frac{x + 1}{2} = \frac{y - 3}{4} = \frac{z + 1}{3}

and

\frac{x + 3}{2} = \frac{y + 2}{6} = \frac{z - 1}{λ} (λ \in R)

is equal to

\frac{k}{\sqrt{633}},

then

k

is equal to ____________.

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 9th April 2019 Shift 1>Q 71

A plane passing though the points

(0, - 1, 0)

and

(0, 0, 1)

and making an angle

\frac{π}{4}

with the plane

y - z + 5 = 0,

also passes through the point

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IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 9th April 2019 Shift 1>Q 72

If the line,

\frac{x - 1}{2} = \frac{y + 1}{3} = \frac{z - 2}{4}

meets the plane,

x + 2 y + 3 z = 15

at a point

P,

then the distance of

P

from the origin is,