Complete the table and show the relation between the volume and temperature at constant pressure. Volume V Temperature T (In Kelvin scale) V T 546 mL 273 K 546 273 = 2 600 mL 300 K 600 300 = 2 640 mL 320 K 640 320 = 2 660 mL 330 K _____

Completed table is: Volume V Temperature T (In Kelvin scale) V T 546 mL 273 K 546 273 = 2 600 mL 300 K 600 300 = 2 640 mL 320 K 640 320 = 2 660 mL 330 K 660 330 = 2 At constant pressure, the volume of a definite mass of a gas is directly proportional to the temperature in Kelvin scale. At constant pressure (P) V T = constant. V = KT

E M B I B E

Chemistry Standard X Part 1>Chapter 2 - Gas Laws and Mole Concept>Exercise

MEDIUM

10th Kerala Board

IMPORTANT

Earn 100

The size of the air bubbles rising from the bottom of an aquarium increases. Can you explain the reason?

Important Questions on Gas Laws and Mole Concept

HARD

10th Kerala Board

IMPORTANT

Chemistry Standard X Part 1>Chapter 2 - Gas Laws and Mole Concept>Exercise

Take a dry bottle (an injection bottle) having a rubber stopper. Fix an empty refill through the rubber stopper. Fill a drop of ink into the lower end of the refill tube, then close the bottle. Dip this arrangement in lukewarm water.

What do you observe?

What is the reason for the rising of the ink upwards?

What did you observe on cooling the bottle after taking it out? Why?

From this, what can you infer about the relation between the volume and temperature of a gas?

MEDIUM

10th Kerala Board

IMPORTANT

Chemistry Standard X Part 1>Chapter 2 - Gas Laws and Mole Concept>Exercise

Complete the table and show the relation between the volume and temperature at constant pressure.

Volume V	Temperature T (In Kelvin scale)	$\frac{V}{T}$
$546 mL$	$273 K$	$\frac{546}{273} = 2$
$600 mL$	$300 K$	$\frac{600}{300} = 2$
$640 mL$	$320 K$	$\frac{640}{320} = 2$
$660 mL$	$330 K$	_____