Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 34

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The solubility product of $AgCl$ is $10^{- 10}$ . What volume of water (in $L$ ) is required to dissolve $2.87 mg$ of $AgCl$ ?

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Important Questions on Equilibrium

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 35

The solubility of

{CaF}_{2} (K_{sp} = 3.4 \times 10^{- 11})

in

0.1 M

solution of

NaF

would be

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 36

The solubility

Fe (OH)_{3}

will be maximum in:

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 37

The

pH

of a solution prepared by adding

1 mole

of

Mg (OH)_{2}

in

1 L

water is

(K_{sp} Mg (OH)_{2} = 1 \times 10^{- 11} \log (2.72 \times 10^{- 4}) = 3.57)

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 38

Solubility of

{As}_{2} S_{3}

in

10^{- 3} {MNa}_{2} S

solution, assuming no hydrolysis of cationic or anionic part is:

(K_{sp} {As}_{2} S_{3} = 16 \times 10^{- 27})

.

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 39

The solubility product of

{Ag}_{2} {CO}_{3}

and

{FeCO}_{3}

in water at

25 ° C

are

4 \times 10^{- 12}

and

2.5 \times 10^{- 11}

, respectively. If

S_{1}

and

S_{2}

are their solubilities in water, respectively when dissolved separately, then

S_{1} / S_{2}

is:

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 40

How many millimoles, of

NaOH

should be added to

1 L

of

0.1 M {FeCl}_{3}

, solution to just start the precipitation of

Fe (OH)_{3} ? K_{sp} [Fe (OH)_{3}] = 8 \times 10^{- 13}

.

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 41

$K_{sp} (SnS) = 10^{- 25}$
$K_{SP} (ZnS) = 1.6 \times 10^{- 24}$

To a solution containing $0.01 {MSn}^{2 +}$ and $0.2 {MZn}^{2 +}, S^{2 -}$ is added gradually. Without changing the volume of solution. Which of the following is correct?

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Alpha Question Bank for Medical: Chemistry>Chapter 5 - Equilibrium>Exercise 2>Q 42

The solubility product of

AgCl

is

1.8 \times 10^{- 10}

. Precipitation of

AgCl

will occur only when equal volumes of solutions of: