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Earn 100

The standard free energy change and standard activation energy for four biochemical reactions are listed in the table below.

Reaction Standard free energy change(kcal/mol) Standard activation energy (kcal/mol)
P -40 18
Q -71 18
R -40 11
S -71 11

A few interpretations are given below. Among these, the most appropriate interpretation is;

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Important Questions on Biomolecules

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Refer to the given graph showing relationship between temperature and enzyme action.

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Select the correct statement regarding 'A' and 'B'.

(i) 'A' shows the rate at which reaction decreases due to denaturation of enzyme molecules.
(ii) 'B' shows the rate at which reaction increases due to decreased kinetic energy of the substrate.
(iii) As temperature rises, more and more enzyme molecules are denatured and 'A' appears to fall.
(iv) 'B' shows the rate at which reaction increases due to increased kinetic energy of the substrate and enzyme molecules.

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Refer to the given graph showing the state of ionisation of Zwitterion.

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Select the correct statements regarding Zwitterion.
(i) Zwitterions can be formed from compounds that contain both acid groups and basic groups in their molecules.
(ii) A zwitterion can act either as proton donor or proton acceptor.
(iii) A monoamine monocarboxylic-amino acid is acid at high as both the groups (amino and carboxyl) lose a proton.
(iv) Amino acids in solution at neutral pH exist predominantly as dipolar ions, the amino group is protonated NH3 and the carboxyl group is deprotonated -COO-

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Study the given data and answer the following question.

A sample of an enzyme called lactase was isolated from the intestinal lining of a calf. Assays were undertaken to evaluate the activity of the enzyme sample. The substrate of lactase is the disaccharide lactose. Lactase breaks a lactose molecule in two, producing a glucose molecule and a galactose molecule.

Two assays were carried out.

Assay 1:

Lactose concentration (% w/v) 15 15 15 15 15 15
Concentration of enzyme sample (% v/v) 0 5 10 15 20 25
Reaction rate μmol glucose sec-1 mL-1 0 25 50 75 100 125

Assay 2:

Lactose concentration (% w/v) 0 5 15 20 25 30
Concentration of enzyme sample (% v/v) 5 5 5 5 5 5
Reaction rate μmol glucose sec-1 mL-1 0 15 25 35 40 40

What are the variables in each of the two assays?

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Study the given data and answer the following question.

A sample of an enzyme called lactase was isolated from the intestinal lining of a calf. Assays were undertaken to evaluate the activity of the enzyme sample. The substrate of lactase is the disaccharide lactose. Lactase breaks a lactose molecule in two, producing a glucose molecule and a galactose molecule.

Two assays were carried out.

Assay 1:

Lactose concentration (% w/v) 15 15 15 15 15 15
Concentration of enzyme sample (% v/v) 0 5 10 15 20 25
Reaction rate μmol glucose sec-1 mL-1 0 25 50 75 100 125

Assay 2:

Lactose concentration (% w/v) 0 5 15 20 25 30
Concentration of enzyme sample (% v/v) 5 5 5 5 5 5
Reaction rate μmol glucose sec-1 mL-1 0 15 25 35 40 40

Which of the following statements can be concluded from the two assays?

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Which of the following assays would you expect to have the highest reaction rate?
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It is said that elemental composition of living organisms and that of inanimate objects (like earth's crust) are similar in the sense that all the major elements are present in both. Then what would be the difference between these two groups?
Choose a correct answer from the following.
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Many elements are found in living organisms either free or in the form of compounds. One of the following is not found in living organisms.
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Amino acids have both an amino group and a carboxyl group in their structure. Which amongst the following is an amino acid?