The successive ionisation energies in $\mathrm{kJ} {\mathrm{mol}}^{-1}$ of an element $\text{P}$ are $740, 1500, 10500, 13600, 18000$ and $21700$. Which ion is the most likely to be formed when $\mathrm{P}$ reacts with chloride?

Successive ionisation energies of an element $\text{'}\mathrm{X}\text{'}$ are given below (in $\mathrm{k} \mathrm{cal}$): 

Electronic configuration of the element $\text{'}\mathrm{X}\text{'}$ is:

How many of the following have greater ${\mathrm{Z}}_{\mathrm{eff}}$ than Silicon atom:

(i) $\mathrm{Na}$ (ii) $\mathrm{Mg}$ (iii) $\mathrm{Al}$ (iv) $\mathrm{P}$ (v) $\mathrm{Cl}$ (vi) $\mathrm{S}$ (vii) $\mathrm{N}$ (viii) $\mathrm{O}$ (ix) $\mathrm{F}$

Where $\mathrm{a}, \mathrm{b}, \mathrm{c}, \mathrm{d}, \mathrm{e}, \mathrm{f}, \mathrm{g}, \mathrm{h}$ are $3^{\mathrm{rd}}$ period elements. If the difference between the atomic numbers of elements $\mathrm{b}$ and $\mathrm{e}$ is $\mathrm{x}$ and the difference between the atomic number of elements $\mathrm{c}$ and $\mathrm{f}$ is $\mathrm{y}.$ What is the value of $\mathrm{x}-\mathrm{y}.$