The time taken by a photoelectron to come out after the photon strikes is approximately

$\mathrm{Statement}-1 :$When ultraviolet light is incident on a photocell, its stopping potential is${\mathrm{V}}_{0 }$and the maximum kinetic energy of the photoelectrons is ${\mathrm{K}}_{\max }.$When the ultraviolet light is replaced by $\mathrm{X}-\mathrm{rays},$ both ${\mathrm{V}}_0$and ${\mathrm{K}}_{\max }$ increase.

$\mathrm{Statement}-2 :$Photoelectrons are emitted with speeds ranging from zero to a maximum value because of the range of frequencies present in the incident light.

This question has $\mathrm{statement} –1 \mathrm{and} \mathrm{statement} –2.$ Of the four choices given after the statements, choose the one that best describes the two statements :

$\mathrm{Statement}-1 :$A metallic surface is irradiated by a monochromatic light of frequency $\mathrm{\nu }>{\mathrm{\nu }}_0$ (the threshold frequency). The maximum kinetic energy and the stopping potential are ${\mathrm{K}}_{\max }$ and ${\mathrm{V}}_0$ respectively. If the frequency incident on the surface is doubled, both the ${\mathrm{K}}_{\max }$ and ${\mathrm{V}}_0$are also doubled.

$\mathrm{Statement}-2 :$The maximum kinetic energy and the stopping potential of photoelectrons emitted from a surface are linearly dependent on the frequency of incident light.