The unit of equivalent conductivity is

The equivalent conductances of two ions at infinite dilution in water at $25°\mathrm{C}$ are given below.

${\mathrm{\Lambda }}_{\mathrm{eq}}^{\infty }\left({\mathrm{Ba}}^{2+}\right)=127.00 \mathrm{S} {\mathrm{cm}}^2/\mathrm{equivalent}$

${\mathrm{\Lambda }}_{\mathrm{eq}}^{\infty }\left({\mathrm{Cl}}^{-}\right)=76.00 \mathrm{S} {\mathrm{cm}}^2/\mathrm{equivalent}$

The equivalent conductance $\left(\mathrm{S} {\mathrm{cm}}^2/\mathrm{equiv}\right)$ of ${\mathrm{BaCl}}_2$ at infinite dilution will be

The emf of the cell

$\mathrm{Ni}\left|{\mathrm{Ni}}^{2+}(1.0 \mathrm{M})\Vert {\mathrm{Au}}^{3+}(1.0 \mathrm{M})\right|\mathrm{Au}$ is $\left[{\mathrm{E}}^{\circ } \mathrm{for} {\mathrm{Ni}}^{2+}/\mathrm{Ni}=-\right.0.25 \mathrm{V}; {\mathrm{E}}^{\circ }$ for ${\mathrm{Au}}^{3+}/\mathrm{Au}=1.5 \mathrm{V}]$

Two electrochemical cells $\mathrm{Fe}/{\mathrm{Fe}}^{2+}\Vert {\mathrm{Cu}}^{2+}/\mathrm{Cu}$ and $\mathrm{Zn}/{\mathrm{Zn}}^{2+}\Vert {\mathrm{Cu}}^{2+}/\mathrm{Cu}$ are connected in series 

$\left({\mathrm{Fe}}^{2+}/\mathrm{Fe}=-0.41 \mathrm{V}, {\mathrm{Zn}}^{2+}/\mathrm{Zn}=-0.76 \mathrm{V}, {\mathrm{Cu}}^{2+}/\mathrm{Cu}=+0.34 \mathrm{V}\right)$. The net emf of this cell is