HARD
11th CBSE
IMPORTANT
Earn 100

The unit of length convenient on the nuclear scale is a fermi: 1 f=10-15 m. Nuclear sizes obey roughly the following empirical relation: r=r0 A1/3 where r is the radius of the nucleus, A its mass number, and r0 is a constant equal to 1.2 f. Show that the rule implies that nuclear mass density is nearly constant for different nuclei. Estimate the mass density of sodium nucleus. Compare it with the average mass density of a sodium atom i.e 0.58×103 kgm-3.

Important Points to Remember in Chapter -1 - Units and Measurements from NCERT PHYSICS PART 1 TEXTBOOK FOR CLASS XI Solutions

1. Unit:

Measurement of any physical quantity is expressed in terms of an internationally accepted certain basic standard called unit.

2. Fundamental Units:

S.No.

Physical Quantity

SI Unit

Symbol

1

Length

Metre

M

2

Mass

Kilogram

Kg

3

Time

Second

S

4

Electric Current

Ampere

A

5

Temperature

Kelvin

K

6

Luminous Intensity

Candela

Cd

7

Amount of Substance

Mole

Mol

3. Supplementary Units:

S.No. Physical Quantity SI Unit Symbol
1 Plane Angle radian r
2 Solid Angle Steradian Sr

4. Metric Prefixes:

S.No. Prefix Symbol Multiplier
1 Centi c 102
2 Milli m 103
3 Micro μ 106
4 Nano n 109
5 Pico p 1012
6 Kilo K 103
7 Mega M 106

5. Errors in measurements:

(i) Values obtained from several measurements are a1,a2, a3. an: Mean value amean= a1+a2+ann

(ii) Absolute error of a measurement Δa1= a1-amean

(iii) Mean absolute error Δamean= Δa1+Δa2+...Δan.n

(iv) Any measurement we take for the physical quantity a may lie between amean+Δamean and amean-Δamean

(v) Relative error in = Δameanamean

(vi) Percentage error = Δameanamean×100%

6. Combination of errors:

(i) If two physical quantities A and B have measured values a±Δa and b±Δb and if Z= A+B and Z is expressed as z±Δz, then z= a+b and Δz= Δa+Δb

(ii) If Z= A-B and Z is expressed as z±Δz, then z= a-b and Δz= Δa+Δb

(iii) If Z= A×B and Z is expressed as z±Δz, then z= a×b and Δz= zΔaa+Δbb

(iv) If Z= A÷B and Z is expressed as z±Δz, then z= a÷b and Δz= zΔaa+Δbb

(v) If Z= An and Z is expressed as z±Δz, then z= an and Δz= nzΔaa