HARD
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The vapour pressure of CS2 at 50°C is 854 torr and a solution of 2.0 gm sulphur in 100 gm of CS2 has vapour pressure 848.9 torr. If the formula of sulphur molecule is Sn, then calculate the value of "n" (approx.) (At. mass of S=32) :-

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Important Questions on Solutions

MEDIUM
How many grams of glucose are required to prepare an aqueous solution of glucose having a vapor pressure of 23.324 mm Hg at 25°C in 100 g of water? The vapour pressure of pure water at 25°C is 23.8 mm Hg.
MEDIUM
For a solution formed by mixing liquids L and M, the vapour pressure of L plotted against the mole fraction of M in solution is shown in the following figure, Here, XL and XM represent mole fractions of L and M, respectively, in the solution. The correct statement(s) applicable to this system is(are) -

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MEDIUM
The vapour pressure of a solution of glucose is 720 mmHg at 100oC. What is the mole fraction of water in this solution?
EASY
Benzene and toluene form nearly ideal solution. At 20°C, the vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 20°C for a solution containing 78 g of benzene and 46 g of toluene (in torr) is
EASY
9 gram anhydrous oxalic acid (mol. Wt. = 90) was dissolved in 9.9 moles of water. If vapour pressure of pure water is P1o the vapour pressure of solution is
EASY
Which of the following statement is true?
MEDIUM
38.4 g of unknown substance (molar mass 384 g mol-1) and 116 g of acetone is used to prepare a solution at 313 K. If vapour pressure of pure acetone (molar mass 58 g mol-1) is 0.842 atmosphere, what is the vapour pressure of solution ?
HARD
At 104.2°C, the vapour pressure of a solution of 7.5 g of a solute in 100 g of water is 740 mm of Hg and Kb=0.55, then the boiling point of the solution is ________
EASY
Two open beakers one containing a solvent and the other containing a mixture of that solvent with a non volatile solute are together sealed in a container. Over time:
MEDIUM
Relative lowering of vapour pressure of a dilute solution of glucose dissolved in 1 kg of water is 0.002. The molality of the solution is
EASY
vapour pressure of water at 293 K is 17535 mm Hg. The vapour pressure of water at 293 K containing 25 g of glucose dissolved in 450 g of water is
MEDIUM
At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg , lowering of vapour pressure will be:
(molar mass of urea =60 g mol-1 )
MEDIUM
The vapour pressure of a solvent decreased by 20 mm of Hg when a non-volatile solute was added to the solvent. The mole-fraction of the solute in the solution is 0.5. What should be the mole-fraction of the solvent for the decrease in the vapour pressure needs to be 10 mm of Hg ?
HARD
The plot of total vapour pressure as a function of mole fraction of the components of an ideal solution formed by mixing liquids X and Y is
EASY
The vapor pressure of a dilute solution of glucose is 750 mm of mercury at 373 K. The mole fraction of the solute is _________
EASY
The solution having lowest vapour pressure amongst the following is
EASY
In which of the following lowering of vapour pressure would be maximum?
EASY
A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A, B and C. The relative lowering of vapour pressure in the presence of these solutes are in the order [Given, molar mass of A=100 g mol-1 ; B=200 g mol-1 ; C=10,000 g mol-1]
MEDIUM
Liquid M and liquid N form an ideal solution. The vapour pressures of pure liquids M and N are 450 and 700 mmHg, respectively, at the same temperature. Then correct statements is:
( xM=Mole fraction of 'M' in solution;
xN=Mole fraction of 'N'in solution;
yM=Mole fraction of 'M' in vapour phase;
yN=Mole fraction of 'N' in vapour phase; )
EASY
The mass of a non-volatile, non-electrolyte solute (molar mass = 50 g mol-1) needed to be dissolved in 114 g octane to reduce its vapour pressure by 75%, is: