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The vapour pressure of pure benzene at $25^{0} C$ is $180 mm Hg$ . The vapour pressure lowering caused by the addition of $25 g$ of a solute (molar mass $= 342$ ) to $250 g$ of benzene is______.

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Important Questions on Solutions

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IMPORTANT

Chemistry Crash Course NEET>Chapter 8 - Solutions>Level 3>Q 12

A small amount of a non-volatile solute is dissolved in

64 .5 {cm}^{3}

of acetone(density:

0 .791 g / {cm}^{3}

). The vapour pressure of this solution at room temperature is

260 mm Hg

, while that of acetone is

285 mm Hg

. What is the molality of the solution?

HARD

NEET

IMPORTANT

Chemistry Crash Course NEET>Chapter 8 - Solutions>Level 3>Q 13

300 K

, vapour pressure of substance

A

0.95 atm

and vapour pressure of substance

B

0.15 atm

. A solution of

A and B

is prepared and allowed to equilibrate with its vapour. The vapour is found to have equal moles of

A and B

. What is lhe mole fraction of

A

in the original solution?

EASY

NEET

IMPORTANT

Chemistry Crash Course NEET>Chapter 8 - Solutions>Level 3>Q 14

0.3

Molal aqueous solution of sucrose boils at

100 . 51^{0} C

. The boiling point of

0.7

molal aqueous solution of sucrose will be______.

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Chemistry Crash Course NEET>Chapter 8 - Solutions>Level 3>Q 15

A solution contains

0.524 g

of camphor

(molar mass = 152 g {mol}^{- 1})

dissolved in

36.8 g

of ether(boiling point

= 34 . 6^{0} C

). The molal elevation constant of ether is

{1.94 K kg mol}^{-1}

. The boiling point of the solution is______

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Chemistry Crash Course NEET>Chapter 8 - Solutions>Level 3>Q 16

0.1 M

solution each of glucose, sodium chloride, sodium sulphate and sodium phosphate are taken; the ratio of depression in freezing point is______

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Chemistry Crash Course NEET>Chapter 8 - Solutions>Level 3>Q 17

The depression in freezing point of a

5 %

aqueous solution of a substance '

A

’ is equal to the depression in freezing point of a

3 %

aqueous solution of a substance '

B

’ If the molecular weight of

B

72 g {mol}^{- 1}

, then the molecular weight of

A

is______.

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IMPORTANT

Chemistry Crash Course NEET>Chapter 8 - Solutions>Level 3>Q 18

The depression of the freezing point of a solvent(boiling point

303 K

) for a particular solution is

0.153 K

. Calculate the molal elevation constant, if the boiling point of the solution is

304.52 K

K_{f} {=1.68 K kg mol}^{-1}

)

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IMPORTANT

Chemistry Crash Course NEET>Chapter 8 - Solutions>Level 3>Q 19

A solution containing

3.56 g

of a polymer in

1

litre of a solvent was found to have an osmotic pressure of

{5.2×10}^{-4}

atmosphere at

300 K

. The molecular mass of the polymer is_____.

{(R=0.082 L atm mol}^{-1} K^{-1})

The vapour pressure of pure benzene at 250C is 180 mm Hg. The vapour pressure lowering caused by the addition of 25 g of a solute (molar mass =342) to 250 g of benzene is______.

Important Questions on Solutions

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The vapour pressure of pure benzene at $25^{0} C$ is $180 mm Hg$ . The vapour pressure lowering caused by the addition of $25 g$ of a solute (molar mass $= 342$ ) to $250 g$ of benzene is______.