The variation of potential with distance $r$ from a fixed point is shown in the figure.

The electric force acting on a point charge of $2 \mathrm{C}$ placed at the origin will be

The electric potential $V$ as a function of distance $x$ (in $\mathrm{metre}$) is given by $V=\left(5x^2+10x–9\right) \mathrm{volt}$. The value of the electric field at $x=1 \mathrm{m}$ would be

A non-conducting ring of radius $0.5 \mathrm{m}$ carries a total charge of $1.11 \times {10}^{-10} \mathrm{C}$ distributed non-uniformly on its circumference producing an electric field $E$ everywhere in space. The value of the line integral ${\oint }_{l=\infty }^{l=0}-\overrightarrow{E}.\mathrm{d}\overrightarrow{\mathrm{l}} (l=0$ being centre of the ring) in volts is (Approximately)

Due to an electric dipole shown in figure, the electric field intensity is parallel to dipole axis