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The vertical height of the projectile at time t is given by y=4t-t2 and the horizontal distance covered is given by x=3t. What is the angle of projection with the horizontal?

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Important Questions on Kinematics

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A bomb is fired from a cannon with a velocity of 1000 m/s making an angle of 30° with the horizontal:
What is the time taken by the bomb to reach the highest point- 
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For a projectile the ratio of maximum height reached to the square of flight time is g=10 m s-2
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If a projectile is thrown such that range R is four times the height h attained then the angle of projection is-
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The range of projectile is 50 m when θ is inclined with horizontal at 15°. What is the range when θ becomes 45°-
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A particle moves in the xy plane with only an x -component of acceleration of 2 ms-2. The particle starts from the origin at t=0 with an initial velocity having an x -component of 8 ms-1 and y -component of -15 ms-1. Velocity of particle after time t is:
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A ball is projected from a certain point on the surface of a planet, at a certain angle with the horizontal surface. The horizontal and vertical displacement x(in meter) and y(in meter), respectively, vary with time t (in seconds) as x=103t, y=10tt2. The maximum height attained by the ball is
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The horizontal and verticle distances travelled by a particle in time t are given by x=6t and y=8t-5t2. If g=10 m/sec2. then the initial velocity of the particle is-
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In the above question the angle with the horizontal at which the projectile is projected is :