There are $3$ bags which are known to contain $2$ white and $3$ black balls; $4$ white and $1$ black balls and $3$ white and $7$ black balls respectively. A ball is drawn at random from one of the bags and found to be a black ball. Then the probability that it was drawn from the bag containing the most black balls is

$A$ and $B$ are two events defined as follows:

$A$: It rains today with $P\left(A\right)=40\%$

$B$: It rains tomorrow with $P\left(B\right)=50\%$

Also, $P($it rains today and tomorrow$)=30\%$

Also, $E_1:P\left(\frac{\left(A\cap B\right)}{\left(A\cup B\right)}\right) \& E_2:P\left(\frac{\left(\left(A\cap \overline{B}\right)\cup \left(B\cup \overline{A}\right)\right)}{\left(A\cup B\right)}\right)$, then which of the following is/are true?

Two numbers are randomly selected and multiplied,

Consider two events $E_1 \& E_2$ defined as

$E_1$:Their product is divisible by $5$

$E_2$: Unit's places of their product is $5$

Which of the following statement is /are correct?