There are five concentric circles that are spaced equally from each other by $2.5 \mathrm{m}$. The innermost circle has a square of side $\sqrt{128} \mathrm{m}$ inscribed in it. If a square need to be inscribed in the outermost circle, what will be its area?

What is the area of this trapezoidal garden (All measurements are in cm)? 

1. $60$ sq.cm
2. $180$ sq.cm
3. $210$ sq.cm 
4. $240$ sq.cm

The perimeter and the breadth of a rectangle are $52 cm$ and $12 cm$ respectively. Find its area in $c{m}^2$.

Quantity $1$: Area of square is $324 {\mathrm{cm}}^2$, whose perimeter is equal to perimeter of rectangle. Length of the rectangle is $4 \mathrm{cm}$ more than breadth of the rectangle. Find the area of rectangle.

Quantity $2$: $320 {\mathrm{cm}}^2$.

The length of rectangle is $80\%$ of diagonal of square of area $1225 {\mathrm{m}}^2$, then find area of rectangle, if it's perimeter is $94\sqrt{2} \mathrm{m}$.