NCERT Exemplar Mathematics - Class 8>Chapter 9 - Comparing Quantities>Exercise>Q 52

EASY

8th CBSE

IMPORTANT

Earn 100

Three times a number is $200 %$ increase in the number, and the one third of the same number is $200 %$ decrease in the number.

50% studentsanswered this correctly

Important Questions on Comparing Quantities

EASY

8th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 8>Chapter 9 - Comparing Quantities>Exercise>Q 53

Simple interest on a given amount is always less than or equal to the compound interest on the same amount for the same time period and at the same rate of interest per annum.

EASY

8th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 8>Chapter 9 - Comparing Quantities>Exercise>Q 54

The cost of a sewing machine is

Rs 7, 000

. Its value depreciates at

8 %

p.a. Then the value of the machine after

2

years is

Rs 5, 924.80

.

EASY

8th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 8>Chapter 9 - Comparing Quantities>Exercise>Q 55

If the discount of

Rs y

is available on the marked price of

Rs x

, then the discount percent is

\frac{x}{y} \times 100 %

.

MEDIUM

8th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 8>Chapter 9 - Comparing Quantities>Exercise>Q 56

Number of students appearing for class

X

CBSE examination increases from

91, 422

in

1999 - 2000

to

11, 6054

in

2008 - 09 .

Increase in the number of students appeared is approximately

27 %

.

EASY

8th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 8>Chapter 9 - Comparing Quantities>Exercise>Q 57

Selling price of

9

articles is equal to the cost price of

15

articles. In this transaction there is profit of

66 \frac{2}{3} %

.

EASY

8th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 8>Chapter 9 - Comparing Quantities>Exercise>Q 58

The compound interest on a sum of

Rs P

for

T

years at

R %

per annum compounded annually is given by the formula

P (1 + \frac{R}{100})

.

EASY

8th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 8>Chapter 9 - Comparing Quantities>Exercise>Q 59

In case of gain, Selling price

= \frac{100 + gain %}{100} \times

cost price.

MEDIUM

8th CBSE

IMPORTANT

NCERT Exemplar Mathematics - Class 8>Chapter 9 - Comparing Quantities>Exercise>Q 60

In case of loss, cost price

= \frac{100 \times Selling price}{100 + 1055 %}

.