EASY
Earn 100

Tile sum of the first five terms of an A.P. is one-sixth the sum of next five terms. If the first term of the A.P. is 5, find the sum of first 30 terms of the A.P.

Important Questions on Sequences and Series

MEDIUM
The sum of all positive integers n for which 13+23++2n312+22++n2 is also an integer is
HARD
If, for a positive integer n, the quadratic equation,

xx+1+x+1x+2+...+x+n-1¯x+n=10n 

has two consecutive integral solutions, then n is equal to:
MEDIUM
The sum of the first 20 terms of the series 1+32+74+158+3116+ is
HARD
The value of  cotΣn=123cot-11+Σk=1n2k  is
HARD
The sum of first 9 terms of the series 131+13+231+3+13+23+331+3+5+... is
EASY
if n is the smallest natural number such that n+2n+3n+.+99n is a perfect square, then the number of digits in n2 is
HARD
Let Sn=113+1+213+23+1+2+313+23+33++1+2+,+n13+23+n3 . If 100 Sn=n, then n is equal to:
HARD
Let ai=i+1i for i=1,2, .,20 . Put p=120a1+a2++a20 and q=1201a1+1a2++1a20. Then
EASY
If ω, is an imaginary cube root of1, then the value of 12-ω2-ω2+23-ω3-ω2+.....+n-1n-ωn-ω2, is
MEDIUM
If the sum of the first 15 terms of the series 343+1123+2143+33+334 3+ is equal to 225K, then K is equal to :
HARD
If n=1 5 1nn+1n+2n+3=k3,  then k is equal to:
HARD
Let A1, A2., Am be non-empty subsets of {1, 2, 3,,100} satisfying the following conditions.

1 The numbers A1,A2,,Am are distinct ;

2 A1,A2,..,Am are pairwise disjoint.

(Here A denotes the number of elements in the set A). Then the maximum possible value of m is
HARD
The values of n=0194712n+21947 is equal to
MEDIUM
Let a1,a2,……a100 be non-zero real numbers such that a1+a2+…+a100=0, Then
MEDIUM
Let a, b, c, d be real numbers such that

k=1nak3+bk2+ck+d=n4

For every natural number n. Then a+b+c+d is equal to
MEDIUM
The largest perfect square that divides 20143-20133+20133-20113++23-13 is-
MEDIUM
The sum of the 24 terms of the series 2+8+18+32+…. Is
MEDIUM
The value of r=1630r+2(r-3) is equal to:
HARD
Let Sk=1 + 2 + 3++kk. If S12+S22++S102=512A, then A is equal to :