The range of a random variable X is { 1 , 2 , 3 … . . . } and P ( X = x ) = c x x ! , for x = 1 , 2 , 3 , … … Then the value of C is

ln ( 2 ) ( where ln denotes the natural log )

ln ( 3 ) ( where ln denotes the natural log )

Let X be a random variable which takes values 1 , 2 , 3 , 4 such that P ( X = r ) = K r 3 where r = 1 , 2 , 3 , 4 then

K = 1 100 and P 1 2 < X < 5 2 ∣ X > 1 = 8 99

K = 1 100 and P 1 2 < X < 5 2 ∣ X > 1 = 8 97

K = 1 99 and P 1 2 < X < 5 2 ∣ X > 1 = 8 99

K = 1 100 and P 1 2 < X < 5 2 ∣ X > 1 = 10 99

The range of a random variable X is { 1 , 2 , 3 … . . . } and P ( X = x ) = c x x ! , for x = 1 , 2 , 3 , … … Then the value of C is

ln ( 2 ) ( where ln denotes the natural log )

ln ( 3 ) ( where ln denotes the natural log )

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Tom and Jerry play a game of alternately throwing an unfair coin. First one to get head wins. If Tom starts the game, he has $62.5 %$ chance of winning the game. Suppose this coin is tossed $5$ times, then the probability of getting exactly $3$ heads is

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Important Questions on Probability

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 32 - Probability>AP EAPCET 2019 (21-Apr Shift-2)>Q 18

The probabilities of having a defective toy in three cartons

A, B, C

are

\frac{1}{3}, \frac{1}{4}, \frac{2}{5}

respectively. If a carton is selected at random and a toy drawn randomly from it is found to be defective, then the probability that it is drawn from carton

B

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 32 - Probability>AP EAPCET 2018 (25-APR Shift-1)>Q 19

A random variable $X$ has the following probability distribution:

$X = x_{i}$	$- 2$	$- 1$	$0$	$1$	$2$
$P (X = x_{i})$	$\frac{1}{6}$	$k$	$\frac{1}{4}$	$k$	$\frac{1}{6}$

The variance of this random variable is

EASY

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 32 - Probability>AP EAPCET 2021 (19-Aug Forenoon)>Q 20

A random variable $X$ has the probability distribution :

$X$	$1$	$2$	$3$	$4$	$5$	$6$	$7$	$8$
$P (X)$	$0.15$	$0.23$	$0.12$	$0.10$	$0.20$	$0.08$	$0.07$	$0.05$

For the events

E = \{X is a prime number\}

and

F = \{X < 4\},

then

P (E \cup F)

EASY

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 32 - Probability>AP EAPCET 2021 (19-Aug Afternoon)>Q 21

A discrete random variable $X$ takes values $10, 20, 30$ and $40$ , with probability $0.3, 0.3, 0.2, 0.2$ respectively. Then the expected value of $X$ is

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 32 - Probability>AP EAPCET - 20 Aug 2021 Forenoon>Q 22

For the random variable $X$ with probability distribution is given by the table

$X = x$	$0$	$1$	$2$	$3$
$P (X = x)$	$K$	$K + \frac{1}{7}$	$2 K$	$\frac{2}{5}$

The mean of $X$ is

EASY

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 32 - Probability>AP EAPCET - 20 Aug 2021 Afternoon>Q 23

The range of a random variable

X

{1, 2, 3 \dots . . .}

and

P (X = x) = \frac{c^{x}}{x!}

, for

x = 1, 2, 3, \dots \dots

Then the value of

C

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 32 - Probability>AP EAPCET 2020 (Sep-23 Shift-1)>Q 24

If on an average

9

mountain climbers out of

10

return safely, what is the probability that with

5

climbers out, at least

4

will return safely?

MEDIUM

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 32 - Probability>AP EAPCET 2020 (Sep-23 Shift-1)>Q 25

If the mean and standard deviation of a binomial distribution are

20

and

4

, respectively, then the number of trials is ________

Tom and Jerry play a game of alternately throwing an unfair coin. First one to get head wins. If Tom starts the game, he has 62.5% chance of winning the game. Suppose this coin is tossed 5 times, then the probability of getting exactly 3 heads is

Important Questions on Probability

Learn and Prepare for any exam you want !

Tom and Jerry play a game of alternately throwing an unfair coin. First one to get head wins. If Tom starts the game, he has $62.5 %$ chance of winning the game. Suppose this coin is tossed $5$ times, then the probability of getting exactly $3$ heads is