Two $5$ molal solutions are prepared by dissolving a non-electrolyte non-volatile solute separately in the solvents $\mathrm{X}$ and $\mathrm{Y}$. The molecular weights of the solvents are $\mathrm{MX}$ and $\mathrm{MY}$, respectively where ${\mathrm{M}}_{\mathrm{X}} =\frac{ 3}{4} {\mathrm{M}}_{\mathrm{Y}}$. The relative lowering of the vapour pressure of the solution in $\mathrm{X}$ is $"\mathrm{m}"$ times that of the solution in $\mathrm{Y}$. Given that the number of moles of solute is very small in comparison to that of solvent, the value of $"\mathrm{m}"$ is: