Two capacitors $C_1$ and $C_2=2C_1$ are connected in a circuit with a switch between them as shown in the figure. Initially, the switch is open and $C_1$ holds a charge $Q$. The switch is closed. At steady state, the charge on each capacitor will be

The figure shows a capacitor of capacitance $\mathrm{C}$ connected to a battery via a switch, having a total charge ${\mathrm{Q}}_0$ on it, in steady-state. When the switch $\mathrm{S}$ is turned from position $\mathrm{A}$ to position $\mathrm{B}$, the energy dissipated in the circuit is

Figure shows charge $\left(\mathrm{q}\right)$ versus voltage $\left(\mathrm{V}\right)$ graph for series and parallel combination of two given capacitors. The capacitances are:

Three capacitances, each of 3 $\mu \text{F}$, are provided. These cannot be combined to provide the resultant capacitance of :

In the circuit shown, charge on the $5\mu \mathrm{F}$  capacitor is :

In the circuit shown, find $C$ if the effective capacitance of the whole circuit is to be $0.5 \mu F.$ All values in the circuit are in $\mu F.$

Figure shows a network of capacitors where the number indicates capacitances in micro Farad. The value of capacitance C if the equivalent capacitance between point A and B is to be $1 \mu F$ is :

The equivalent capacitance between $A$ and $B$ is,

A parallel plate capacitor $C$ with plates of unit area and separation $d$ is filled with a liquid of dielectric constant $K=2$, the level of liquid is$\frac{d}{3},$initially. 
Suppose, the liquid level decreases at a constant speed $v$, the time constant as a function of time is

The equivalent capacitance of the combination of the capacitors is