EASY
12th Uttar Pradesh Board
IMPORTANT
Earn 100

Two cells, having the same e.m.f. are connected in series through an external resistance R . Cells have internal resistances r1 and r2 r1>r2 respectively. When the circuit is closed, the potential difference across the first cell is zero. The value of R is

50% studentsanswered this correctly

Important Questions on Current Electricity

EASY
12th Uttar Pradesh Board
IMPORTANT
A group of N cells, whose emf varies directly with the internal resistance as per the equation EN=1.5 rN, are connected as shown in the figure. The current I in the circuit is

Question Image
EASY
12th Uttar Pradesh Board
IMPORTANT
Two similar cells, whether joined in series or in parallel, have the same current through an external resistance of  2 Ω. The internal resistance of each cell is
EASY
12th Uttar Pradesh Board
IMPORTANT
Two identical cells whether connected in parallel or in series gives the same current, when connected to an external resistance 1.5 Ω. Find the value of internal resistance of each cell.
EASY
12th Uttar Pradesh Board
IMPORTANT
A battery consists of a variable number (n) of identical cells, each having an internal resistance r connected in series. The terminal of the battery is short-circuited. A graph of current versus the number of cells will be as shown in figure.
EASY
12th Uttar Pradesh Board
IMPORTANT
In the electric circuit shown, each cell has an emf of 2 V and internal resistance of 1 Ω. The external resistance is 2 Ω. The value of the current I is (in ampere)

Question Image
HARD
12th Uttar Pradesh Board
IMPORTANT
n identical cells each of emf E and internal resistance r are connected in series to form a row. m such rows are connected in parallel to form a battery of N=mn cells. This battery is connected to an external resistance R. (i) What is the emf of this battery and how much is its internal resistance?
HARD
12th Uttar Pradesh Board
IMPORTANT
n Cells each of emf E and internal resistance r are connected in series to form a row. m such rows are connected in parallel to form a battery of  N=mn Cells. This battery is connected to an external resistance: R. Show that current I flowing through the external resistance R is given by
I=NemR+nr
HARD
12th Uttar Pradesh Board
IMPORTANT
n identical cells, each of emf E and internal resistance r, are connected in series to a resistor R. Deduce an expression for the internal resistance r of one cell in terms of the current I in the circuit.