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Two coherent sources of different intensities send waves which interfere. The ratio of maximum intensity to the minimum intensity is 25. the intensities of the sources are in the ratio -

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Important Questions on Physics

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In a Young's double slit experiment slit separation 0.1 mm, one observes a bright fringe at angle 140 rad by using light of wavelength λ1. When the light of wavelength λ2 is used a bright fringe is seen at the same angle in the same set up. Given that λ1 and λ2 are in visible range 380 nm to 740 nm, their values are:
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In a Young's double slit experiment, slits are separated by 0.5 mm, and the screen is placed 150 cm away. A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen. The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide is:
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In the Young's double slit experiment using a monochromatic light of wavelength λ , the path difference ( in terms of an integer n ) corresponding to any point having half the peak intensity is
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Consider a Young's double slit experiment as shown in figure. What should be the slit separation d in terms of wavelength λ such that the first minima occurs directly in front of the slit (S1) ?

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The distance between two coherent sources is 1 mm. The screen is placed at a distance of 1 m from the sources. If the distance of the third bright fringe is 1.2 mm from the central fringe, the wavelength of light used is
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A beam of mono-energetic electrons, which have been accelerated from rest by a potential U, is used to form an interference pattern in a Young's double slit experiment. The electrons are now accelerated by potential 4U. Then, the fringe width,
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In Young's double-slit experiment, in an interference pattern, the second minimum is observed exactly in front of one slit. The distance between the slits is d and the distance between source and screen is D. The wavelength of the light source used is
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In a double slit experiment, when light of wavelength 400 nm was used, the angular width of the first minima formed on a screen placed 1 m away was found to be 0.2°. What will be the angular width of the first minima, if the entire experimental apparatus is immersed in water? μwater=43
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The interference pattern is obtained with two coherent light sources of intensity ratio, n. In the interference pattern, the ratio, Imax−IminImax+Imin will be
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A monochromatic light source S of wavelength 440 nm is placed slightly above a plane mirror M as shown below. Image of S in M can be used as a virtual source to produce interference fringes on the screen. The distance of source S from O is 20.0 cm and the distance of screen, from O is 100.0 cm (the figure is not to scale). If the angle θ=0.50×10-3 radians, then the width of the interference fringes observed on the screen is:
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Using monochromatic light of wavelength λ , an experimentalist sets up the Young's double slit experiment in three ways as shown.
If she observes that y⁡ = β ′ , the wavelength of light used is :

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A parallel beam of light is incident on a tank filled with water up to a height of 61.5 mm as shown in the figure below. Ultrasonic waves of frequency 0.5 MHz are sent along the length of the water column using a transducer placed at the top, and they form longitudinal standing waves in the water. Which of the schematic plots below best describes the intensity distribution of the light as seen on the screen? Take the speed of sound in water to be 1,500 m s-1.
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In Young’s double-slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single-slit diffraction pattern is :
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Young's double slit experiment is first performed in air and then in a medium other than air. It is found that 8th bright fringe in the medium lies where 5th dark fringe lies in air. The refractive index of the medium is nearly
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In Young's double-slit experiment, the distance between slits and the screen is 1 m and monochromatic light of wavelength 600 nm is being used. A person standing near the slits is looking at the fringe pattern. When the separation between the slits is varied, the interference pattern disappears for a particular distance d0 between the slits. If the angular resolution of the eye is 160°, then the value of d0 is close to
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In a Young’s double slit experiment, the separation between the slits is 0.15 mm . In the experiment, a source of light of wavelength 589 nm is used and the interference pattern is observed on a screen kept 1.5 m away. The separation between the successive bright fringes on the screen is:
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In a double – slit experiment, at a certain point on the screen the path difference between the two interfering waves is 18th of a wavelength. The ratio of the intensity of light at that point to that at the center of a bright fringe is:
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Electrons accelerated from rest by an electrostatic potential are collimated and sent through a Young's double slit experiment. The fringe width is ω. If the accelerating potential is doubled, then the width is now close to:
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In a double-slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double-slit within the central maxima of a single-slit pattern?
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The intensity at the maximum in a Young's double slit experiment is I0. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance D=10d ?