Two positively charged particles, each of mass 1 . 7 × 10 - 27 kg and carrying a charge of 1 . 6 × 10 - 19 C are placed at a distance d apart. If each experiences a repulsive force equal to its weight, find the value of d .

Let m A be the mass of the first particle and q A be the charge on it, m B be the mass of second particle and q B be the charge on it and d is distance of separation between both the particles. Given, m A = m B = 1 . 7 × 10 - 27 kg and q A = q B = 1 . 6 × 10 - 19 C Also, Given that both the particles experiences a repulsive force which is equal to its weight F = m A × g = m B × g = 1 . 7 × 10 - 27 × 9 . 8 N Using Coulomb's law, F = k q A q B d 2 ⇒ d 2 = k q A q B F ⇒ d 2 = 9 × 10 9 1 . 6 × 10 - 19 2 1 . 7 × 10 - 27 × 9 . 8 ⇒ d = 0 . 118 m

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Beta Question Bank for Medical: Physics>Chapter 22 - Electrostatics>BEGINNER'S BOX - 2>Q 8

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Two equal point charges $Q = + \sqrt{2} μ C$ are placed at each of the two opposite corners of a square and equal point charges $q$ at each of the other two corners. What must be the value of q so that the resultant force on $Q$ is zero?

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Beta Question Bank for Medical: Physics>Chapter 22 - Electrostatics>BEGINNER'S BOX - 2>Q 9

In the given figure three point charges are situated at the corners of an equilateral triangle of side $10 cm$ . Calculate the resultant force on the charge at $B$ . What is its direction?

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Beta Question Bank for Medical: Physics>Chapter 22 - Electrostatics>BEGINNER'S BOX - 2>Q 10

Two positively charged particles, each of mass

1.7 \times 10^{- 27} kg

and carrying a charge of

1.6 \times 10^{- 19} C

are placed at a distance

d

apart. If each experiences a repulsive force equal to its weight, find the value of

d

.

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Beta Question Bank for Medical: Physics>Chapter 22 - Electrostatics>BEGINNER'S BOX - 3>Q 1

$A B C$ is a right angled triangle. Calculate the magnitude of force on charge - $Q$ .

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Beta Question Bank for Medical: Physics>Chapter 22 - Electrostatics>BEGINNER'S BOX - 3>Q 2

Charge $Q$ of mass $m$ revolves around a point charge $q$ due to electrostatic attraction. Show that its period of revolution is given by $T^{2} = \frac{16 π^{3} ε_{0} m R^{3}}{Q q}$ .